Answer:
B would be a *dependent* event, and A would be an *independent* event.
Step-by-step explanation:
Independent events are separate events where the outcome in either event does not affect the other's probability. The opposite, where the outcome of the one event affects the other's probably, is dependent.
For Option A, taking a tile out and then replacing it does not affect the probability that the same tile will be picked for the 2nd picking.
For Option B, taking a tile out of the bag and then picking another tile are 2 separate events and both have different probabilities for picking identical tiles.
Therefore, Option B is dependent and Option A is independent.
You multiply vectors and scalar simply by multiplying each component by that scalar:
Finally, you sum two vectors by summing the correspondent coordinates:
Money collected independent
tickets sold dependent
Answer:
A
Step-by-step explanation:
The first answer is correct because we have a decay factor.
The sample is losing mass, so the number that is being multiplied by a power of x must be less than 1.
If the second answer were used, then the sample would be gaining mass.
Step-by-step explanation:
solution:- from LHS 1-cos²x/sinx
∵ 1-cos²x = sin²x
∴ sin²x /sinx = sinx
from RHS tanx × cosx
∵tanx = sinx×cosx
∴ sinx/ cosx × cosx = sinx
Since, LHS = RHS proved ___
