There are 31 days in January
0.875 is the density for this question
Answer:
Step-by-step explanation:
Leaving leap years, a year contains 365 days.
For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of
![\frac{1}{365}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B365%7D)
a) Probability that exactly 3 people have same birthday = ![\frac{1}{365^3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B365%5E3%7D)
Each day is independent of the other
And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = ![\frac{1}{365^3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B365%5E3%7D)
Expected value of days = np = ![\frac{1}{365^2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B365%5E2%7D)
b) Distinct birthdays is binomail with p =1/365 and n = 365
Hence
expected value = np =1
Answer:
A.)4x+8
C.)8x+12
Step-by-step explanation:
Same steps you did
Answer:
A store receives a shipment of 5,000 MP3 players. In a previous shipment of 5,000 MP3 players, 300 were defective. A store clerk generates random numbers to simulate a random sample of this shipment. The clerk lets the numbers 1 through 300 represent defective MP3 players, and the numbers 301 through 5,000 represent working MP3 players. The results are given.
948 628 87 4,987 938 468 3,589 298 2,459 2,286
Based on this sample, how many of the MP3 players might the clerk predict would be defective?
The manager would expect
defective players in the shipment.