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gladu [14]
3 years ago
14

Pre calc prove 4tan^4x+tan^2x-3=sec^2x(4tan^2x-3)

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0
4tan^4 x + tan^2 x - 3 = sec^2 x (4tan^2 x - 3)
The left side factors into:
(tan² x + 1)(4tan² x - 3) = sec² x (4tan² x - 3)

The (4tan² x - 3) factors cancel each other to leave:
tan² x + 1 = sec² x
This is one of the Pythagorean Identities, so this is proved.

I hope that helps!! :)
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Step-by-step explanation:

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Step-by-step explanation

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Set it up like this:

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This allows the equation to be more organized, and you can check your work by canceling the units.

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