Please help <br> I WILL MARK THE BRAINLEST

What percent of one hour is 25 minutes?

igomit [66]

Answer:

41.667% or 42%

Step-by-step explanation:

25/60

simplify

5/12 = 41.667

3 0

3 years ago

PLEASE HELP

Oliga [24]

Answer:

The answer your looking for is, <u><em>C.</em></u>

3 0

3 years ago

Read 2 more answers

HELP PLEASE!!

Feliz [49]

Answer:

6163.2 years

Step-by-step explanation:

A_t=A_0e^{-kt}

Where

A_t=Amount of C 14 after “t” year

A_0= Initial Amount

t= No. of years

k=constant

In our problem we are given that A_t is 54% that is if A_0=1 , A_t=0.54

Also , k=0.0001

We have to find t=?

Let us substitute these values in the formula

0.54=1* e^{-0.0001t}

Taking log on both sides to the base 10 we get

log 0.54=log e^{-0.0001t}

-0.267606 = -0.0001t*log e

-0.267606 = -0.0001t*0.4342

t=\frac{-0.267606}{-0.0001*0.4342}

t=6163.20

t=6163.20 years

PLEASE MARK BRAINLY

3 0

4 years ago

Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The

xxTIMURxx [149]

(20, 16), they are the only two numbers that have a difference of 4 and take half of each of those numbers and add them together it will equal 18.

Hope this helped :)

5 0

4 years ago

Read 2 more answers

IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual is randomly chosen. Let X =

allochka39001 [22]

Using the normal distribution, it is found that there is a 0.4038 = 40.38% probability that the person has an IQ score between 92 and 108.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 100, \sigma = 15$ .

The probability that the person has an IQ score between 92 and 108 is the <u>p-value of Z when X = 108 subtracted by the p-value of Z when X = 92</u>, hence:

X = 108:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{108 - 100}{15}$

Z = 0.53

Z = 0.53 has a p-value of 0.7019.

X = 92:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{92 - 100}{15}$

Z = -0.53

Z = -0.53 has a p-value of 0.2981.

0.7019 - 0.2981 = 0.4038.

0.4038 = 40.38% probability that the person has an IQ score between 92 and 108.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

4 0

2 years ago

Please help I WILL MARK THE BRAINLEST