Please help <br> I WILL MARK THE BRAINLEST

What is the gcf of 3/7 and 4/9?

LiRa [457]

Answer:

1/63

Step-by-step explanation:

There are a couple of ways to do this.

Look for the GCF of the numerators when a common denominator is used.

GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)

GCF(3/7, 4/9) = 1/63

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Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

(4/9)/(3/7) = 1 remainder 1/63*

(3/7)/(1/63) = 27 remainder 0

The GCF is 1/63.

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* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

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<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

3 0

2 years ago

Question in image! Thanks for help! (Also im posting more questions like this so if these are easy for you keep a eye out on my

AlexFokin [52]

Answer:

c. x=50; m< LOK = 114

Step-by-step explanation:

(x+64) + 66 = 180

x + 130 = 180

x = 50

4 0

3 years ago

Read 2 more answers

Use the given values to complete the table for the function below<br> y=2x^2+8x-5

artcher [175]

What your gonna want to do is any where there is an x you are going to put in the number from the x column. You then solve for y and that is the answer for that number you used for x that would be your y

4 0

1 year ago

Andrew bought a shirt and a pair of pants that cost $3675. The shirt costs double the pants. How much do they each cost?

vampirchik [111]

Answer: $7350

Step-by-step explanation:

$3675 x 2 = $7350

5 0

2 years ago

Read 2 more answers

The auto parts department of an automotive dealership sends out a mean of 4.2 special orders daily. What is the probability that

gregori [183]

The probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

<h3>What are some of the properties of Poisson distribution?</h3>

The Poisson distribution is a discrete probability distribution that describes the likelihood of a specific number of events occurring in a specified span of time or space, if these events occur at a constant mean rate and regardless of the time since the last occurrence.

Let X ~ Pois(λ)

Then we have:

E(X) = λ = Var(X)

Since standard deviation is the square root (positive) of variance,

Thus,

The standard deviation of X = $\sqrt{\lambda}$

Its probability function is given by

$f(k; λ) = Pr(X = k) = \dfrac{\lambda^{k}e^{-\lambda}}{k!}$

Given the mean is 4.2.

We have to find the probability that on any day, the number of special orders sent out will be exactly 3. Therefore, the value of x will be 5.

Using the Poisson distribution,

$P(x) = \dfrac{e^{-\lambda}\lambda ^x}{x!}\\\\P(5) =\dfrac{e^{-4.2}(4.2)^5}{5!}\\\\P(5) = 0.1633$

Hence, the probability that, for any day, the number of special orders sent out will be exactly 3 is 0.1633.

Learn more about Poisson distribution here:

brainly.com/question/7879375

#SPJ1

5 0

2 years ago

Please help I WILL MARK THE BRAINLEST