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padilas [110]
3 years ago
8

A jar that contains quarters and dimes is worth $7.15. If there are a total of 40 coins,

Mathematics
2 answers:
kherson [118]3 years ago
7 0

Answer:

21 quarters and 19 dimes

Step-by-step explanation:

Create a system of equations where q is the number of quarters and d is the number of dimes.

0.25q + 0.1d = 7.15

q + d = 40

Solve by elimination by multiplying the bottom equation by -0.25

0.25q + 0.1d = 7.15

-0.25q - 0.25d = -10

Add them together and solve for d:

-0.15d = -2.85

d = 19

Then, plug in 19 as d into the second equation to solve for q:

q + d = 40

q + 19 = 40

q = 21

So, there are 21 quarters and 19 dimes

klasskru [66]3 years ago
4 0

Answer:

21 Quarters, 19 Dimes.

Step-by-step explanation:

21 x .25 = 5.25

19 x .10 = 1.90

5.25 + 1.90 = 7.15

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There are 9 apples. there are 6 fewer apples than oranges. how many oranges are there
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Answer:

  2)  (b) -7

  3)  (b) 14

Step-by-step explanation:

2) The sum is found by adding the numbers together. Your calculator can help if you can't do it in your head. I usually find it easier to add the positive and negative numbers separately. Of course the 0 can be ignored.

  18 + 0 -4 -12 +6 -15 = (18 +6) -(4 +12 +15) = 24 -31 = -7

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3) Apparently, we are to assume that George's percentage will apply to the next 40 pitches. Then ...

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3 years ago
In a random sample of 16 residents of the state of Washington, the mean waste recycled per person per day was 2.8 pounds with a
kakasveta [241]

Answer: The required confidence interval would be (2.72,2.89)

Step-by-step explanation:

Since we have given that

Mean = 2.8 pounds

Standard deviation = 0.24 pounds

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We need to find the 80% confidence interval for the mean waste.

z=1.341

So, the confidence interval will be

\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=(2.8\pm 1.341\times \dfrac{0.24}{\sqrt{16}})\\\\=(2.8\pm 1.314\times 0.06)\\\\=(2.8-0.07884,2.8+0.07884)\\\\=(2.72116,2.87884)

Hence, the required confidence interval would be (2.72,2.89)

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3 years ago
Quadrilateral WXYZ has the coordinates W(b, b), X(4b, b), Y(3b, 0), and Z(0, 0).
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The length of side WX in Quadrilateral WXYZ is 3b units.

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The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

AB=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Given the coordinates W(b, b), X(4b, b), Y(3b, 0), and Z(0, 0). The length of WX is:

WX=\sqrt{(b-b)^2+(4b-b)^2}=3b

The length of side WX in Quadrilateral WXYZ is 3b units.

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