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padilas [110]
3 years ago
8

A jar that contains quarters and dimes is worth $7.15. If there are a total of 40 coins,

Mathematics
2 answers:
kherson [118]3 years ago
7 0

Answer:

21 quarters and 19 dimes

Step-by-step explanation:

Create a system of equations where q is the number of quarters and d is the number of dimes.

0.25q + 0.1d = 7.15

q + d = 40

Solve by elimination by multiplying the bottom equation by -0.25

0.25q + 0.1d = 7.15

-0.25q - 0.25d = -10

Add them together and solve for d:

-0.15d = -2.85

d = 19

Then, plug in 19 as d into the second equation to solve for q:

q + d = 40

q + 19 = 40

q = 21

So, there are 21 quarters and 19 dimes

klasskru [66]3 years ago
4 0

Answer:

21 Quarters, 19 Dimes.

Step-by-step explanation:

21 x .25 = 5.25

19 x .10 = 1.90

5.25 + 1.90 = 7.15

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Step-by-step explanation:

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Simplifying

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Let f(x) = - 4x - 1 and g(x) = x2 + 3.
mariarad [96]

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- 77

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Dafna11 [192]

Answer:

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Step-by-step explanation:

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