All categories

3 years ago

How to rename 82 thousands

Mathematics

2 answers:

dezoksy [38]3 years ago

8 0

⇒82 thousand

→1 Thousand=1,000

=82 × 1000

=82,000

⇒82 thousand is renamed as 82,000.

shutvik [7]3 years ago

5 0

82,000
Hope i helped today!
-Good Luck!

You might be interested in

For what values of x is the expression below defined?<br> √x+4÷√1-x

wariber [46]

Answer:

x=1

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which fraction shoes unit rate that is equal to the ratio 18:2

kati45 [8]

Answer: 9/1

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Select the locations on the number line to plot the points 2, 1, and −4 .

rodikova [14]

Answer:

-5-4-3-2-1 0 1 2 3 4 5

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

14 POINTS ASAP WHAT IS THE MEASURE OF ANGLE A

sashaice [31]

Wow...we have lots of numbers to go through. we know that a 6 sided figure is a hexagon and the interior angles add up to be 720°. so.....

∠A + ∠B + ∠ C + ∠D + ∠E + ∠F = 720°
(x - 60) + (x - 40) + 130 + 120 + 110 + (x - 20) = 720
3x + 240 = 720 (combined all like terms)
3x = 480 (subtracted 240 from both sides)
x = 160 (divided both sides by 3)

put the value of x into ∠A (x - 60) = 160 - 60 = 100

∠A = 100°

7 0

3 years ago

A sample of eight workers in a clothing manufacturing company gave the following figures for the amount of time(in minutes) need

lilavasa [31]

Answer:

$10.108 < \mu < 13.892$

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

We have the following distribution for the random variable:

$X \sim N(\mu , \sigma=0.45)$

And by the central theorem we know that the distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=12$

The sample deviation calculated $s=2.268$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=8-1=7$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that $t_{\alpha/2}=2.36$

Now we have everything in order to replace into formula (1):

$12-2.36\frac{2.268}{\sqrt{8}}=10.108$

$12+2.36\frac{2.268}{\sqrt{8}}=13.892$

So on this case the 95% confidence interval would be given by (10.108;13.892)

$10.108 < \mu < 13.892$

7 0

3 years ago