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mars1129 [50]
3 years ago
9

Simplify (2√5+3√7)^2

Mathematics
2 answers:
Westkost [7]3 years ago
5 0
(2 sq. root 5 + 3 sq. root 7)(2 sq. root 5 + 3 sq. root 7)

4•sq root 25 + 6 sq. root 35 + 6 sq. root 35 + 9 sq. root 49

4 • 5 + 12 sq. root 35 + 9 • 7

20 + 12 sq. root 35 + 63.

I believe this would be the solution.
Anna35 [415]3 years ago
3 0
The answer is: 83 + 12√35

(a + b)² = a² + 2ab + b²

In (2√5 + 3√7)², a = 2√5, b = 3√7

Just substitute a and b:
(a + b)² = a² + 2ab + b² = (2√5)² + 2 * 2√5 * 3√7 + (3√7)² = 
            = 2²√5² + 2 * 2 * 3 * √5 * √7 + 3²√7² =
            = 4 * 5 + 12 * √(5*7) + 9 * 7 =
            = 20 + 12 *√35 + 63 =
            = 83 + 12√35
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6 0
3 years ago
Suppose a circle has a radius of 13 inches. How far would a 24 inch chord be from the center of the circle? (Hint: Draw a diagra
lys-0071 [83]

Answer:

Step-by-step explanation:

Directions

  • Draw a circle
  • Dear a chord with a length of 24 inside the circle. You just have to label it as 24
  • Draw a radius that is perpendicular and a bisector through the chord
  • Draw a radius that is from the center of the circle to one end of the chord.
  • Label where the perpendicular radius to the chord intersect. Call it E.
  • You should get something that looks like  the diagram below. The only thing you have to do is put in the point E which is the midpoint of CB.

Givens

AC = 13 inches                   Given

CB = 24 inches                  Given

CE = 12 inches                    Construction and property of a midpoint.

So what we have now is a right triangle (ACE) with the right angle at E.

What we seek is AE

Formula

AC^2 = CE^2 + AE^2

13^2 = 12^2 + AE^2

169 = 144 + AE^2                     Subtract 144 from both sides.

169 - 144 = 144-144 + AE^2     Combine

25 = AE^2                                Take the square root of both sides

√25 = √AE^2

5 = AE

Answer

The 24 inch chord is 5 inches from the center of the circle.

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