2 answers:
(2 sq. root 5 + 3 sq. root 7)(2 sq. root 5 + 3 sq. root 7)
4•sq root 25 + 6 sq. root 35 + 6 sq. root 35 + 9 sq. root 49
4 • 5 + 12 sq. root 35 + 9 • 7
20 + 12 sq. root 35 + 63.
I believe this would be the solution.
The answer is: 83 + 12√35
(a + b)² = a² + 2ab + b²
In (2√5 + 3√7)², a = 2√5, b = 3√7
Just substitute a and b:
(a + b)² = a² + 2ab + b² = (2√5)² + 2 * 2√5 * 3√7 + (3√7)² =
= 2²√5² + 2 * 2 * 3 * √5 * √7 + 3²√7² =
= 4 * 5 + 12 * √(5*7) + 9 * 7 =
= 20 + 12 *√35 + 63 =
= 83 + 12√35
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