3 years ago

What is the solution of log2 (3x-7) =3

Mathematics

2 answers:

Valentin [98]3 years ago

7 0

Answer:

x = 5

Step-by-step explanation:

because the log is base 2 you can remove the log by raing 2 to the power of each side:

$2^{log2 (3x-7)} = 2^{3}$

the 2 and log2 cancel leaving:

$3x-7 = 2^{3}$

this means we can now solve through simple algebra:

$3x-7 = 8\\3x = 8 + 7\\3x = 15\\3x/3 =15/3\\x = 5$

hammer [34]3 years ago

5 0

The Solution X = 5.

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