Greetings!
When reflecting a shape over the x-axis, you simply change the number to its opposite positive/negative equivalent.
This means that the new co-ordinates would be (-5,1) , (-5,4) and (-2,4).
Hope this helps!
4x=251
251-84=167
4x=167
X=41.75
One tire will cost $41.75
Answer:
Given below
Step-by-step explanation:
The algebraic identity is (a-b)^2
= a^2 + b^2 - 2ab
So it'll be,
(x-4)^2
= x^2 + (4)^2 - (2)(x)(4)
= x^2 -8x + 16
or x^2 +16 -8x
missing side is
mi .
<u>Step-by-step explanation:</u>
Here we have the following info from the figure: A right angled triangle with following dimensions
![Perpendicular = x](https://tex.z-dn.net/?f=Perpendicular%20%3D%20x)
![base = \sqrt{122}](https://tex.z-dn.net/?f=base%20%3D%20%5Csqrt%7B122%7D)
![Hypotenuse = 15](https://tex.z-dn.net/?f=Hypotenuse%20%3D%2015)
By Pythagoras Theorem :
![Hypotenuse^2 = Perpendicular^2 + base^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%20%3D%20Perpendicular%5E2%20%2B%20base%5E2)
⇒ ![Hypotenuse^2 = Perpendicular^2 + base^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%20%3D%20Perpendicular%5E2%20%2B%20base%5E2)
⇒ ![15^2 = x^2 + (\sqrt{122})^2](https://tex.z-dn.net/?f=15%5E2%20%3D%20x%5E2%20%2B%20%28%5Csqrt%7B122%7D%29%5E2)
⇒ ![225 = x^2 + 122](https://tex.z-dn.net/?f=225%20%3D%20x%5E2%20%2B%20122)
⇒ ![x^2 = 225-122](https://tex.z-dn.net/?f=x%5E2%20%3D%20225-122)
⇒ ![x^2 = 103](https://tex.z-dn.net/?f=x%5E2%20%3D%20103)
⇒ ![(x^2)^\frac{1}{2} = (103)^\frac{1}{2}](https://tex.z-dn.net/?f=%28x%5E2%29%5E%5Cfrac%7B1%7D%7B2%7D%20%3D%20%28103%29%5E%5Cfrac%7B1%7D%7B2%7D)
⇒ ![x} = (103)^\frac{1}{2}](https://tex.z-dn.net/?f=x%7D%20%3D%20%28103%29%5E%5Cfrac%7B1%7D%7B2%7D)
⇒ ![x} = 10.15](https://tex.z-dn.net/?f=x%7D%20%3D%2010.15)
Therefore, missing side is
mi .
Answer:
Step-by-step explanation:
hello
calculate x : 3x+2 =5
means : 3x+2-2 =5-2
3x = 3
so : x = 3/3 =1
1 is the element in domain has the image 5 under function f(x)= 3x+ 2