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Zigmanuir [339]
3 years ago
8

If a^b= b^a and a = 2b then find the value of a^2+b^2a) 20b) 30c) 28d) 24​

Mathematics
1 answer:
g100num [7]3 years ago
8 0

Answer:

\large \boxed{\sf \bf \  \ a^2+b^2=20 \ \ }

Step-by-step explanation:

Hello, please consider the following.

a^b=b^a\\\\\text{ We can replace a by 2b.}\\\\(2b)^b=2^b\cdot b^b=b^{2a}=b^2\cdot b^b\\\\\text{ Let's assume that b is different from 0 and we can divide by }b^b \\ \\ \text{ both sides of the equation, and it come.}\\\\2^b=b^2\\\\\text{ We find b = 2 and then a = 4, So}\\\\a^2+b^2=4^2+2^2=16+4=20

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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