9514 1404 393
Answer:
D. 81/m^7
Step-by-step explanation:
The applicable rules of exponents are ...
(ab)^c = (a^c)(b^c)
(a^b)^c = a^(bc)
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
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Using these, your expression simplifies to ...
I need a better picture, it is hard to see..
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
To learn more on derivatives: brainly.com/question/25324584
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Answer:
D bc you keep going up by 60m/1hr
Step-by-step explanation:
The phase shift is the value of the angle when the variable
in the angle is zero.
The angle in the sin function in this equation is (pi X + 2).
When the variable 'X' is zero, the angle is 2 .
So the phase shift of this sin function is 2 (of whatever
the unit of the angle is ... 2 degrees, 2 radians, etc.)
