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Let y = f(x)
y = ln(3x)
Exchange place with x and y.
x = ln(3y)
Solve for y.
y = (e^x)/3
Replace y with the inverse notation.
f^(-1) x = (e^x)/3
Done.
Answer:
hello there
your answer is <u>1</u>
Step-by-step explanation:
hope it helps....
thanks for the free points!!!
Answer:
Center at (4, 7) and radius is √49, or 7
Step-by-step explanation:
Didn't you mean (x-4)² + (y-7) ² = 49?
Comparing (x-4)² + (y-7) ² = 49
to (x - h)^2 + (y - k)^2 = r^2, we see that the center is at (h, k) => (4, 7) and that the radius is √49, or 7.
Answer:
Choose f(x) = 11x + 1
Step-by-step explanation:
Note that we will simply plug the value of 2 into the equation for February:
f(2) = 11(2) + 1 = 23
And plug the value of 6 into the equation for June:
f(6) = 11(6) + 1 = 67
Note how the points on the graph seem to match up with these values. If we evaluate following the same style for each:
f(3) = 11(3) + 1 = 34
f(4) = 11(4) + 1 = 45
f(5) = 11(5) + 1 = 56
Note, these values seems to be very close in approximation to the graph points for each month.
The other three functions return values that are just to far away from what are represented in the graph.
Cheers.
