3 years ago

I am a polygon that connects with the bases of a polyhedron

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

7 0

Answer:

I am a prism.

Step-by-step explanation:

A Prism are polyhedra that have:

Two parallel faces; which are polygons and are called bases

The rest of the faces that are parallelograms and are the side faces.

baherus [9]3 years ago

4 0

It is a pyramid. a polygon meets with a polyhedron and make a pyramid

You might be interested in

Let n = 5. What is the value of 10 + 15 ÷ n – 2? A. 3 B. 6 C. 11 D. 15 need help

Nataly_w [17]

11 hope dis helped u fam

7 0

4 years ago

Read 2 more answers

A cube has a volume of greater than 125 centimeters cubed. what are the possible lengths of the side of that cube?

ioda

The length is 5 because 5 cubed equals 125.

6 0

3 years ago

Consider the system of equations. y = –2x + 4, 3y + x = –3 Which statement is true of this system of equations?

Alexandra [31]

Answer:

the second equation converted to slope-intercept form is y = -1/3x -1

Step-by-step explanation:

9 0

3 years ago

Which is greater a bottle containing 64 fluid ounces or bottle containing two liters of water

suter [353]

Answer:

2 liters, 64 fl. ounces would be converted to liter by 1.8927059 Liters

Step-by-step explanation:

7 0

3 years ago

Simplify completely sqrt of 20Y^8

brilliants [131]

Answer:

Final answer is $2y^4 \sqrt{5}$ .

Step-by-step explanation:

Given expression is $\sqrt{20y^8}$ .

Now we need to smplify the given expression $\sqrt{20y^8}$ .

So begin with factoring 20 into two parts so that one part is perfect square number.

$\sqrt{20y^8}$

$=\sqrt{4 \times 5y^8}$

$=\sqrt{4 y^8} \times \sqrt{5}$

$=2y^4 \times \sqrt{5}$

Hence final answer is $2y^4 \sqrt{5}$ .

3 0

3 years ago