Answer:
Sabemos que:
L es el largo de la avenida.
En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:
L - L/2 = L/2.
En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:
L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L
En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:
(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L
Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:
(2/40)*L = 200m
L = 200m*(40/2) = 4,000m
The answer to your question is 0.1
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
y=4x+2
Step-by-step explanation:
To find the slope of a line, you would do y₂-y₁/x₂x₁
This would be 2-6/0-1...
So your answer would be -4/-1
After simplifying, your slope is 4.
To write this in slope-intercept form, that would be y=4x+2
Y=9r, r=r
9r+r=30
10r=30
r=30/10
r=3(Red Sox)
yankee=9(3)=27
