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BartSMP [9]
3 years ago
8

To solve 35-19, jack used 35-20 what did he do next

Mathematics
2 answers:
Kay [80]3 years ago
8 0
Then he got a sum of -1 (or negative one)
ladessa [460]3 years ago
3 0
He added one to his answer! 35-19 is 16, 35-20 is 15
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\left(x^{10}+10y^{12}\right)^2

\gray{\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2}

\gray{a=x^{10},\:\:b=10y^{12}}

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\black{\mathrm{Simplify}\:\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2:}

\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2

\gray{\left(x^{10}\right)^2=x^{20}}

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=x^{20}+20x^{10}y^{12}+100y^{24}

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