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Flura [38]
3 years ago
7

Given f(x) = 3x + 1, solve for x when f(x) = 7.

Mathematics
2 answers:
irakobra [83]3 years ago
4 0

Answer:

f(7) = 22 or x =2

Step-by-step explanation:

  1. f(x) = 3x + 1
  2. f(7) = 3(7) + 1
  3. f(7) = 21 + 1
  4. f(7) = 22

<u>Or if the equation meant it like this:</u>

  1. f(x) = 3x + 1
  2. 7 = 3x + 1
  3. 6 = 3x
  4. 2 = x
kirill [66]3 years ago
3 0

Answer:

f(7) = 22

Step-by-step explanation:

1. f(x) = 3x + 1

2. f(7) = 3(7) + 1

3. f(7) = 21 + 1

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Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

5 0
3 years ago
Read 2 more answers
Craig went bowling with $25 to spend he rented shoes for $5.25 and paid $4dollars for each game what was the greatest number of
BlackZzzverrR [31]
He would play 4 games.
3 0
3 years ago
Read 2 more answers
Solve this system of equations:
SpyIntel [72]

y=2x so replacr the -y with -2x so 2x+6 is 8x. :)

7 0
3 years ago
Which of the following statements is not true concerning the equation x2−c=0 for c&gt;0? A. The​ left-hand side of this equation
Firdavs [7]

Answer:

The correct option is;

B. This equation is not considered to be a quadratic equation because it is not in the form a·x² + b·x + c = 0

Step-by-step explanation:

A. The given equation, x² - c = 0, can be presented in the form of the difference of two squares as follows;

(x + √c)·(x - √c) = 0

B. The equation x² - c = 0, is a quadratic equation because it is a polynomial equation of degree 2

C.  The equation x² - c = 0 can always be factored as (x + √c)·(x - √c) = 0

D. Where c > 0, the equation x² - c = 0 can by the square root property as follows;

x² - c = 0

x² = c

x = √c

5 0
3 years ago
Assignment
RSB [31]
12 pounds

1 bag of grapes = 4 pounds

Martin bought 3 bags so:
4 pounds x 3 = 12 pounds

Hope this helps
5 0
3 years ago
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