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navik [9.2K]
3 years ago
8

THIS IS URGENT, I REALLY NEED HELP!

Mathematics
1 answer:
ladessa [460]3 years ago
3 0

Answer:

9.667

Step-by-step explanation:

All I did was plug the function into Desmos and it have me my answer by graphing it

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Can someone help me answer this question
Alex_Xolod [135]

Answer:

your answer is B

Step-by-step explanation:

your question is asking the y and x intercepts in other words where your line crosses the x and y axis respectively therefore your x is positive 2 and your y is -5

(2,0) and (0,-5)

8 0
3 years ago
The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of
julia-pushkina [17]

Answer:

180.4~cm^2

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

A=2\pi rh

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

A=2\pi rh+2\pi r^2

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

Now we calculate the side area of the can:

A=2\pi (3.25)(8.5)

A=173.6~cm^2

We need to add the 0.8 cm overlap to the total area already calculated. This overlap has 0.8 cm of width and 8.5 cm of height, so this overlap area is:

A_o= 0.8*8.5=6.8~cm^2

The total area of the label is:

A=173.6~cm^2+6.8~cm^2=180.4~cm^2

The area of the label is \mathbf{180.4~cm^2}

5 0
2 years ago
A coin is tossed 10 times. 4 of the 10 tosses result in heads.
goblinko [34]
A. It is less than the theoretical probability because
5 0
3 years ago
Read 2 more answers
A force of 15 N will stretch a rubber band 10 cm ​(0.10 ​m). Assuming that​ Hooke's law​ applies, how far will an 18​-N force st
Solnce55 [7]

Answer: a) extension = 0.12m, b) work done = 2.16 J

Step-by-step explanation: according to hooke's law, provided that elastic limit is kept constant force (f) is proportional to extension (e).

F = ke, k = F / e.

F1/e1 = F2/e2

F1 = 15 N, e1 = 0.10m, F2= 18 N, e2 =?

15/0.10 = 18/e2

e2 = 18 * 0.10/ 15

e2 = 1.8/15

e2 = 0.12m.

Work done at this extension = F2 * e2

Work done = 18 * 0.12 = 2.16 J

4 0
3 years ago
On a fishing trip, Mariko caught 24 fish. She caught some rockfish averaging 2.5lbs and some bluefish averaging 8lb. The total w
Snezhnost [94]

Answer:

Holaaaaaa

Step-by-step explanation:

3 0
3 years ago
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