Answer:
xy^(2)z^(6)
Step-by-step explanation:
i hope that helps you :)
Answer:
The quadratic equation in terms of v is v² + 2 v + 180 = 0
Step-by-step explanation:
Given as :
The distance between house to the school = d = 6 km
The uniform speed = v km/h
So, Time = 
or, t = 
Or, t = 
<u>Now, Again</u>
The speed is increase by 2 km/h
i.e speed = (v + 2) km/h
So, Time taken = t' = (t -
)hours
i.e t' = (t -
)hours
Now, Time = 
So, (t -
) = 
Or, (t -
) = 
Or ,
-
= 
Or ,
=
Or, (90 - v) × (v + 2) = 6 × 15 v
Or, 90 v - 180 - v² - 2 v = 90 v
Or, v² + 2 v + 180 = 90 v - 90 v
Or, v² + 2 v + 180 = 0
So, The quadratic equation in terms of v
v² + 2 v + 180 = 0
Hence The quadratic equation in terms of v is v² + 2 v + 180 = 0 Answer
Answer:
see below
Step-by-step explanation:
Usually, we're concerned about the relationship of y to x. Here, the question is asking you to consider the relationship of x to y.
The easiest way to find the answer to this one is to check the given explanations to see which is true. You can pretty much ignore the first row of the table and just look at the second row where x=5 and y=15.
- it is NOT TRUE that x is 3 times y (5 is not 3 times 15)
- it is TRUE that x is 1/3 of y (5 is 1/3 of 15)
- it is NOT TRUE that x is 5 times y (5 is not 5 times 15)
- it is NOT TRUE that x is 1/5 of y (5 is not 1/5 of 15)
_____
If you know your multiplication tables, you know that 15 = 3×5, so ...
5 = 15/3
5 = (1/3) × 15
The relationship of these numbers should not be a mystery.
Answer:
<h2>Let the common ratio b x thus the part becomes</h2><h2>=5x and 4x respectively</h2>
<h2>Thus,ATQ</h2>
<h2>5x+4x= 54</h2>
<h2>9x=54</h2>
<h2>x= 6</h2>
<h2>Sam will get is £30 (putting the value of x)</h2><h2>and Bethan will get £24</h2>
Answer:
Oh gosh. Im not positive but I think it would be 43:25. Please dont get mad at me if its wrong!
Step-by-step explanation:
I am so sorry if its wrong but im not very sure :-(