Answer:
Possible lowest volume = 0.19 cm
Possible highest volume = 0.21 cm
Explanation:
given data
volumetric pipette uncertainty = 0.01 cm³
total volume = 0.20 cm³
solution
we will get here Possible lowest and highest volume that is express as
Possible lowest volume = total volume - uncertainty .....................1
Possible highest volume = total volume + uncertainty ....................2
put here value in both equation and we get
Possible lowest volume = 0.20 cm - 0.01 cm
Possible lowest volume = 0.19 cm
and
Possible highest volume = 0.20 cm + 0.01 cm
Possible highest volume = 0.21 cm
The answer is 9.03 × 10²⁴<span> molecules.
</span><span>Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance.
Make the proportion.
</span><span>6.02 × 10²³ molecules per 1 mol
</span>x per 15 mol
6.02 × 10²³ molecules : 1 mol = x : 15 mol
x = 6.02 × 10²³ molecules * 15 mol * 1 mol
x = 90.3 × 10²³ molecules
x = 9.03 × 10 × 10²³ molecules
x = 9.03 × 10²³⁺¹ molecules
x = 9.03 × 10²⁴ molecules
Wavelength is measured from crest to crest.
Not all DNA codes for proteins
Explanation:
- DNA (Deoxy Ribonucleic acid) is the genetic material present in all the eukaryotes.
- An experiment conducted in the 1960s proved that most parts of DNA are composed of long strings of repeated sequence which does not code for proteins.
- The process involves in coding for a protein are the transcription of DNA to RNA, then translation followed by protein synthesis. There are enzymes involved in these processes.
- As per the latest study, it states that only 1 per cent of genes code for proteins rest 99 per cent is called the non-coding DNA.
The chemical symbol for sodium bicarbonate is NaHCO₃. Its molar mass is calculated by adding the product of the molar mass of each of the component and the number of moles. That is,
molar mass of NaHCO₃ = (1 mol Na)(23 g Na/1 mol Na) + (1 mol H)(1 g H/ 1 mol H) + (1 mol C)(12 g C/1 mol C) + (3 mol O)(16 g O/1 mol O)
molar mass of NaHCO₃ = 84 g/mol
Same is to be done with sodium carbonate which has a molar mass of Na₂CO₃
molar mass of Na₂CO₃ = (2 mol Na)(23 g Na/1 mol Na) + (1 mol C)(12 g C/1 mol C) + (3 mol O)(16 g O/1 mol O)
molar mass of Na₂CO₃ = 106 g/mol
The decomposition of sodium bicarbonate to sodium carbonate is shwon below,
2NaHCO₃ --> Na₂CO₃ + H₂O + CO₂
Through conversion factors and dimensional analysis,
(1.678 g NaHCO₃)(1 mol NaHCO₃/84 g NaHCO₃)(1 mol Na₂CO₃/2 mol NaHCO₃)(106 g NaHCO₃/1 mol NaHCO₃)
= 1.06 g Na₂CO₃
<em>ANSWER: 1.06 g Na₂CO₃</em>