Answer:
![[Pb^{2+}]=3.9 \times 10^{-2}M](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%3D3.9%20%5Ctimes%2010%5E%7B-2%7DM)
this is the concentration required to initiate precipitation
Explanation:
⇄
Precipitation starts when ionic product is greater than solubility product.
Ip>Ksp
Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.
This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.
![Ip=[Pb^{2}][2Cl^-]^2=Ksp](https://tex.z-dn.net/?f=Ip%3D%5BPb%5E%7B2%7D%5D%5B2Cl%5E-%5D%5E2%3DKsp)

lets solubility=S
![[Pb^{2+}] = S](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%20%3D%20S)
![[Cl^-]=2S](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D2S)
![Ksp=[Pb^{2+}]\times [Cl^-]^2](https://tex.z-dn.net/?f=Ksp%3D%5BPb%5E%7B2%2B%7D%5D%5Ctimes%20%5BCl%5E-%5D%5E2)


![S=\sqrt[3]{\frac{Ksp}{4} }](https://tex.z-dn.net/?f=S%3D%5Csqrt%5B3%5D%7B%5Cfrac%7BKsp%7D%7B4%7D%20%7D)

this is the concentration required to initiate precipitation
Answer:
Scandium(III) fluoride, ScF3, is an ionic compound. It is slightly soluble in water but dissolves in the presence of excess fluoride to form the ScF63− anion.
hope it will help you......
Answer:
Approximately
.
Explanation:
Balanced equation for this reaction:
.
Look up the relative atomic mass of elements in the limiting reactant,
, as well as those in the product of interest,
:
Calculate the formula mass for both the limiting reactant and the product of interest:
.
.
Calculate the quantity of the limiting reactant (
) available to this reaction:
.
Refer to the balanced equation for this reaction. The coefficients of the limiting reactant (
) and the product (
) are both
. Thus:
.
In other words, for every
of
formula units that are consumed,
of
formula units would (in theory) be produced. Thus, calculate the theoretical yield of
in this experiment:
.
Calculate the theoretical yield of this experiment in terms of the mass of
expected to be produced:
.
Given that the actual yield in this question (in terms of the mass of
) is
, calculate the percentage yield of this experiment:
.
Answer:
The functional group present in Cinnamon are : Aromatic , alkene , aldehyde
The functional group present in Almonds : Aromatic , aldehyde
The functional group present in DHA : Ketone , alcohol
Explanation:
<u>Almond :</u>
Chemical formula : 
It contain : A benzene ring (Aromatic) , a -CHO group (aldehyde)
<u>Cinnamon Sticks</u> :
Chemical Formula : 
It contain : A benzene ring (Aromatic) ,an alkene group (C=C) , a -CHO group (aldehyde)
<u> </u><u>DHA:</u>
Chemical Formula : 
It contain : Alcohol group (-OH) , ketone group (C=O)