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son4ous [18]
3 years ago
14

What is the scale factor in dilation? A). 1/6 B). 1/3 C). 3 D). 6

Mathematics
2 answers:
Tresset [83]3 years ago
8 0
Its C.
We can see the pre image is 2.5 x 3. The image is 7.5 x 9. 7.5/3 is 2.5 and 9/3 is 3.
Lelechka [254]3 years ago
3 0
I think it is C as 9/3=3
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• 1 hour = 60 minutes
Nataly [62]

1 mile = 1.6 kilometers so 24*1.6 = 38.4
<em>24 miles = 38.4 kilometers</em>

1 kilometer = 1000 meters so 38.4*1000 = 38,400 meters
<em>38.4 kilometers = 38,400 meters

</em>1 hour = 60 minutes so 2*60 = 120
<em>2 hours = 120 minutes
</em>
To calculate meters per minute, divide.
38,400 / 120 = 320

So that means that Calvin's approximate speed is 320 meters per minute.

3 0
3 years ago
Amin fills up his gas tank with 6 gallons of gas for a cost of $13. How much would it cost to fill a 16-gallon tank?
kotykmax [81]

Answer:

34.66

Step-by-step explanation:

divide 13 by 6 then multiply that by 16

4 0
3 years ago
At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel
Alexeev081 [22]
Use Law of Cooling:
T(t) = (T_0 - T_A)e^{-kt} +T_A
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
42 = (80-20)e^{-3k} +20 \\  \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\  \\ k = -\frac{1}{3} ln (\frac{11}{30})

Substituting k back into cooling equation gives:
T(t) = 60(\frac{11}{30})^{t/3} + 20

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\  \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80
Solve for x:
x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80
Sub back into original cooling equation, x = T(t)
-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20
Solve for t:
60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3}  = 60 \\  \\  (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\  \\  \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\  \\ \\  t = 4.959

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
8 0
4 years ago
Which value for x makes the sentence true? 1/10 + x = 1/7
alexandr1967 [171]

Answer:

3/70

Step-by-step explanation:

change 1/10 and 1/7 so the denominator (bottom number) is the same.  1/10= 7/70 and 1/7= 10/70 so you need 3/70 to make the two numbers equal.

6 0
3 years ago
What is the measure of angle p?
Pavlova-9 [17]

the answer to the question is 67.38

6 0
3 years ago
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