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ExtremeBDS [4]
3 years ago
13

2sin^2 2x=2 In the domain [0, 2pi)

Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0
Please type this as 2(sin 2x)^2=2      <span>2sin^2 2x=2 is confusing.

Reducing this expression:  (sin 2x)^2 = 1

Taking the sqrt of both sides, sin 2x = plus or minus 1

If sin 2x = 1, then 2x must be pi/2 or 3pi/2, and so x must be pi/4 or 3pi/4.

Now you do this for sin 2x = -1.</span>
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Cups come in packages if 12 and lids come in packages of 15. What is the least number of cups and lids that corrine can buy if s
Valentin [98]
What you need to do is find the smallest multiple that they both have (i forgot what that is called) list them like this:
12: 24 36 48 60 72 
15: 30 45 60 75 
60 is the lowest number that they both can multiply to
60 cups/lids is the answer
3 0
3 years ago
Read 2 more answers
Please help im stuck on this question​
FrozenT [24]

Answer:

A

Step-by-step explanation:

Slope is the first y - the second y divided by the first x- the second x. Therefore we take -8-4= -12 and -7-0= -7. Using the formula, we get -12/-7. The negatives cancel out and we get 12/7 which is A.

3 0
2 years ago
Suppose y = 2x +10. Find y if x = -2.
liubo4ka [24]

If x = -2, y = 6.


To solve this quesiton, we need to find the value of y if x is equal to -2. We can do this by substiuting the value of x and then solving.


y = 2 (-2) + 10


y = -4 + 10


y = 6

5 0
3 years ago
Read 2 more answers
Solve the equation <br><br>9y^3+8y=4y+18y^2
kari74 [83]
9y^3+8y=4y+18y^2
9y^3-18y^2+4y=0

*Divide the whole thing by y

9y^2-18y+4=0

*use quadratic formula to solve
3 0
3 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

4 0
3 years ago
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