The answer is
B, C, and D
3x + 5 = 23
5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23
(you add 5 to 3x)
If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:
3x + 5 = 23 Subtract 5 on both sides
3x + 5 - 5 = 23 - 5
3x = 18 Divide 3 on both sides to get "x" by itself

x = 6
1 and a fourth because 3 3/4 devided by three equals 1 1/4
660 would be the nearest ten. you round up because the final number is with 5 or greater. if the final number was 4 or less, you would round down. I hope this helped you
The answer should be on Photomath