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ExtremeBDS [4]
3 years ago
13

2sin^2 2x=2 In the domain [0, 2pi)

Mathematics
1 answer:
djverab [1.8K]3 years ago
8 0
Please type this as 2(sin 2x)^2=2      <span>2sin^2 2x=2 is confusing.

Reducing this expression:  (sin 2x)^2 = 1

Taking the sqrt of both sides, sin 2x = plus or minus 1

If sin 2x = 1, then 2x must be pi/2 or 3pi/2, and so x must be pi/4 or 3pi/4.

Now you do this for sin 2x = -1.</span>
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Show/prove that for any integer x, x^2 - x is even.

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