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3 years ago

12

In one day's work at the nursery, sale and mary together potted 74 plants. If dale planted 48 of those plants how many did mary

plant.

2 answers:

love history [14]3 years ago

8 0

Answer:

mary planted 26

Step-by-step explanation:

74 total so if dale plants 48 mary had to plant the rest so you do 74 - 48= 26

xenn [34]3 years ago

7 0

Answer:

Mary potted 26 of the plants.

Step-by-step explanation:

74 - 48 = 26

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Answer:

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3 days

Step-by-step explanation:

<u>Given:</u>

Initial amount of bacteria = 50000
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f(x) = 50000*2^x

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2 years ago

I need help on this please help

kotykmax [81]

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4

Step-by-step explanation:

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2 years ago

Read 2 more answers

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klemol [59]

Answer:

Step-by-step explanation:

1a. 25/50 =x/100

25*100= 2500/50= 50

A= 50%

1b. 35/40 = x/100

35*100= 3500/40= 87.5

A=87.5%

2a. 15/20= x/100

20*5= 100; 15*5= 75

A=75%

2b. 25/70= x/100

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3a. 15/80= x/100

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4a. 70/80 =x/100

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3 years ago

Would you please help me with this quiz answer, I will really appreciate if you do.

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Answer:

a . domain 5,0,7,9,0

range -2,-2,-4,8,2

b. domain 2,4,8,9

range 1,2,4,11

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because function is a relationship in which each domain element occurs only once.

<h3>b is a function</h3>

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2 years ago

An art history professor assigns letter grades on a test according to the following scheme.A: Top 5% of scoresB: Scores below th

adoni [48]

Answer:

Grade B score:

$76 \leq x \leq 89$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73.3

Standard Deviation, σ = 9.7

We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

B: Scores below the top 5% and above the bottom 62%

We have to find the value of x such that the probability is 0.62

$P( X > x) = P( z > \displaystyle\frac{x - 73.3}{9.7})=0.62$

$= 1 -P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.62$

$=P( z \leq \displaystyle\frac{x - 73.3}{9.7})=0.38$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 73.3}{9.7} = 0.305\\\\x = 76.26$

We have to find the value of x such that the probability is 0.05

$P(X < 0.95) = \\\\P( X < x) = P( z < \displaystyle\frac{x - 73.3}{9.7})=0.95$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 73.3}{9.7} = 1.645\\\\x = 89.26$

Thus, the numerical value of score to achieve grade B is

$76 \leq x \leq 89$

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3 years ago