Help me please!!!! i dont now the answer

Equation

konstantin123 [22]

Answer:

10x+8=4x+(-4).

10×+8=4x-4.

collect like terms.

10x-4x=-4-8.

6x=-12.

x=-12/6.

x=-2.

7 0

2 years ago

What is 10:40 plus 7:15 in time?

sp2606 [1]

Answer:

5:55

Step-by-step explanation:

10 plus 7 in time is 5 and 15 plus 40 is 55

4 0

2 years ago

Read 2 more answers

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

2 years ago

A baseball collector took inventory of all of his baseball cards along with the value of each card. The box plot represents the

love history [14]

Answer: less than 25%

Step-by-step explanation:

The box plot can be read as follows:

The first black dot is the minimum value.

The first half of the rectangle is the lower quartile.

The line that separates the two rectangles is the median.

The second half of the rectangle is the upper quartile

The final point is the maximum.

Knowing that each quartile represents about the 25% of the elements for the set, we can see that both lower and upper quartile (and the 25% of the elements that come after the upper quartile) cost more than $45.

Then we know that at least the (25% + 25% + 25%) = 75% of the cards in the collection cost more than $45.

And we also have elements that are not in the lower quartile that cost more than $45, but we can not determine the percentage that they represent.

So we can only conclude that more than the 75% of the collection costs more than $45.

Now we want to know the percentage of the baseball cards valued at less than $45.

So if more than 75% is valued at more than $45.

Then less than 25% is valued at less than $25.

8 0

2 years ago

Select the best possible first step to solving the system by first eliminating the x variable. 3x − 9y = 6 2x − 11y = 6

Klio2033 [76]

The first step would be to add 3x and 2x i believe but I am not sure

5 0

2 years ago