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Ray Of Light [21]
3 years ago
7

Help me please!!!! i dont now the answer

Mathematics
1 answer:
Marat540 [252]3 years ago
7 0
-1/10 is your answer .   
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A circle that has a center at the point (3, -2) with a radius of 6. Write an equation for the circle.
crimeas [40]

Answer:

(x – 3)^2+ (y +2)^2 = 36

Step-by-step explanation:

Given data

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r^2,

where (h, k) represents the coordinates of the center of the circle

h=3

k=-2

r= 6

Substitute

(x – 3)^2+ (y – (-2))^2 = 6^2

(x – 3)^2+ (y +2)^2 = 36

Hence the expression for the equation of the circle is

(x – 3)^2+ (y +2)^2 = 36

5 0
3 years ago
What is -3+5y+2x+2y?​
Natasha_Volkova [10]

Answer:

The answer is -3 + 7y +2x

Step-by-step explanation:

3 0
3 years ago
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What is the gcf of two prime numbers give an example
bonufazy [111]

Answer: 1

  • For example, the GCF of 3 and 5 is 1.
4 0
3 years ago
An image point has coordinates B'(7, -4). Find the coordinates of its pre-image if the translation used was (x + 4, y + 5).
Anna11 [10]

Answer:

The coordinate of pre-image is, B(3 , -9).

Step-by-step explanation:

Given an image point has coordinate B'(7, -4).

We have to find the coordinates of its pre-image:

The rule of translation on pre-image (x, y) is given by;

B(x, y) \rightarrow B'(x + 4, y + 5)

then;

(7, -4) = (x+4, y+5)

on comparison we have;

x+4 = 7 and y + 5 = -4

First solve for x;

x + 4 = 7

Subtract 4 from both sides we have;

x + 4 -4 =7-4

Simplify:

x = 3

To solve for y;

y+5 = -4

Subtract 5 from both sides we get;

y = -9

Therefore, the coordinate of pre-image is, B(3, -9)

8 0
4 years ago
Read 2 more answers
Please help answer and explain am begging you ​
Airida [17]
1,6,7 are positive
2,9 are negative
3,4,5,8 are undefined
7 0
3 years ago
Read 2 more answers
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