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Naily [24]
3 years ago
5

On his drive from Montpelier, Vermont, to Columbia, South Carolina, Arthur averaged 51 mph. If he had been able to average 60 mp

h, he would have reached his destination 3 hr earlier. What is the driving distance between Montpelier and Columbia?
Mathematics
1 answer:
Llana [10]3 years ago
4 0

Answer:

Distance between Montpelier and Columbia is 1020

Step-by-step explanation:

51 mi/hr average:

d = 51 t  

60 mi/hr average:

d t = 60*(t-3)

Substitute (1) into (2)  

   51 t =  60*(t-3)

   51 t =  60 t + 180

   9 t  =  180

   t    =   20

d = 51 t

   = 51 (20)

   = 1020

let see distance is 1020 lets check

51 t = 60 * (t-3)

51 (20)= 60* (20-3)

1020   = 60*17

1020 = 1020

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<span>we have that

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e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

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360nº/3 = 120nº --> add 120º for z2 angle, again for z3
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z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

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<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

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7 0
3 years ago
A cable company uses the formula S = 20,000 (1 + 0.08)y to estimate the number
vlada-n [284]

Answer:

C. Every year the number of subscribers is estimated to increase by 8% over the

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Using the formula :

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The expression : (1 + 0.08)^y

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4 0
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5 0
2 years ago
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4 0
2 years ago
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hope this helps
4 0
3 years ago
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