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ZanzabumX [31]
3 years ago
5

K & Christian each have a garden of the same size and shape cake grows flowers one and six her of her garden Christian grows

flowers in one and three of her garden
Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

Christian will grow more flower as she utilizes all her garden area for the flower growth.

Step-by-step explanation:

Flower growth is difficult process as it involves great care by a gardener. Christian also grows flowers in her three garden which are available to her. She has same size flower which she grows in her garden.

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If f(x)3(=- Vx-3, complete the following statement:x + 2f(19) ==Answer here
Digiron [165]
Explanation

This exercise is about evaluating a function at a particular argument. To do that, we replace the variable with the argument in the formula of the function, and simplify.

Let's do that:

\begin{gathered} f(19)=\frac{3}{19+2}-\sqrt[]{19-3}, \\  \\ f(19)=\frac{3}{21}-\sqrt[]{16}, \\  \\ f(19)=\frac{1}{7}-4, \\  \\ f(19)=\frac{1-28}{7}, \\  \\ f(19)=-\frac{27}{7}\text{.} \end{gathered}Answerf(19)=-\frac{27}{7}\text{.}

8 0
1 year ago
An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th
butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that \pi = 0.2

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}

0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}

\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}

(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}

n = 5615

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now \pi = 0.12, n = 5615.

We have to find M.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 2.81\sqrt{\frac{0.12*0.88}{5615}}

M = 0.012

7 0
3 years ago
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