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timurjin [86]
3 years ago
8

Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive.

after the loop terminates , it prints out, separated by a space and on a single line, the sum of all the even integers read and the sum of all the odd integers read. declare any variables that are needed. assume the availability of a variable , stdin, that references a scanner object associated with standard input.
Computers and Technology
1 answer:
zysi [14]3 years ago
5 0
Procedure SumEvenOdd(stdin: array [0..100] of integer)
var
   i, sum_even, sum_odd: integer;

begin
   for i := 0 to 100 do begin
       if stdin[i] < 0 then
           break;
       if stdin[i] mod 2 = 0 then //even number
          sum_even := sum_even +  stdin[i]
       else 
          sum_odd := sum_odd +  stdin[i]; 

       ShowMessage('sum of even is ' + IntToStr(sum_even) + ' ' + 'sum of odd                                  is' + IntToStr(sum_odd) ) ;
   end; 

end
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the daily interest rate would be 47% / 365 / 100 = .0012876712 per day.

this assumes 365 days in a year, which is the standard assumption that i know of.

the future value of 750 for 275 days would be based on the formula of f = p * (1 + r) ^ n

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n is the number of time periods (days in this case).

the formula becomes:

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it's what she owes.

the interest rate on the loan is that value minus 750 = 318.440089.

that's how much extra she needs to pay in addition to whatever fees she was charged.

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