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alexira [117]
3 years ago
13

Solve the system by substitution 5x-2y=-22 -x+y=5

Mathematics
1 answer:
Gre4nikov [31]3 years ago
6 0
Are they two different questions
You might be interested in
Plese help me thank you!
lilavasa [31]

Answer:

y=2x

Step-by-step explanation:

Every y value is double the x value on top.

y=6:
6 = 3 × ?

? = 2

y=10:

10 = 5 × ?

? = 2

And so on....

So the equation that represents this data is :

y=2x

8 0
2 years ago
Which ratio is higher 15:20 or 12:16. for 35 points
Margarita [4]

To find which ratio is higher, we can first convert the ratios into fractions (that makes it easier, at least for me) and then simplify the fractions and see which one is greater.

Since ratios are basically division, 15:20 = \frac{15}{20}, and

12:16 = \frac{12}{16}

Now we simplify these fractions. 15 and 20 have a GCF of 5, so taking out the common number gives us the simplified fraction of \frac{3}{4}.

12 and 16 have a GCF of 4, so taking out the common number gives us the simplified fraction of \frac{3}{4}. Since \frac{3}{4} = \frac{3}{4}, these ratios are the same.

8 0
3 years ago
Which experiment describes a binomial experiment?
marshall27 [118]
Answer: the last option.
A binomial experiment is an experiment with only two possible outcomes.

In the first option, there is three possible outcomes (i.e. A, B, C)
In the second option, there is four poissible outcomes (i.e. ace, king, queen, jack)
The third option has six possible outcomes (i.e. six faces of a die)
In the last option, there are two possible outcomes (i.e. '2 number cubes')
6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
3 years ago
ANSWER ONLY IF U KNOW I RLLY NEED HELP THIS IS THE LAST OF MY POINTS.
Ostrovityanka [42]
Sure the answer is 2 4.5
7 0
3 years ago
Read 2 more answers
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