First: f(2) is same as f(x=2) so all we have to do is to express x=2 in f(x)
f(2) = 3*2 + 2 = 8
Second
f^(-1) (3) is inverse function. first we solve f(x) for x.
let f(x) be equal to some variable m
m = (2x -7)/3
3m = 2x - 7
2x = 3m + 7
x = (3m + 7)/3
now we write:
f^-1(x) = (3x + 7)/3
x=3
f^-1(3) = 16/3
Third
2y + 14 = 4y - 2
we just solve for y
2y = 16
y = 8
Now we take that f(x) = y because we both write to be the functions of x
that means that First and third have same result.
It diverges; it does not have a sum. the sum of a geometric series is given by a /(1-r) where a is the first term and the r is the ratio between the terms. r=3 in the series you have given . The absolute value of r must be less then 1 for a geometric series to converge.
for 6
in a
given
slope(m)=1
point=(2,-4)=(x1,y1)
we know
equation of straight line
y-y1=m(x-x1)
y+4=1(x-2)
y+4=x-2
therefore x-y-6=0 is the required equation
substituting with ax+by+c=0 we get
a=1
b= -1
c= -6
Answer:

Step-by-step explanation:
The parent function is given as:

We want to find a new function that results after shifting f(x), 2 units to the right.
Let that function be g(x), then

We replace x by x-2 in f(x) to get:

When we simplify, we obtain:

<span>Surface area</span> = 2πr(h+r) = 2 * 3.14 * 3(8+3) = 207.24 yd²