' B ' is the only choice on the list that tells you a definite place, where you could go to pick up the object or meet somebody.
But in order to use it, you also have to know where the origin of coordinates is ... the point (0, 0) .
__________
No, I'm wrong about that. You have to know where SOME other point is, but that doesn't have to be (0, 0).
Answer:
yes, radio waves and x-rays are type of light.
Answer:
x = 4.32 [m]
Explanation:
We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force = 700 [N]
m = mass = 2030 [kg]
a = acceleration [m/s²]
Now replacing:
![F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]](https://tex.z-dn.net/?f=F%3Dm%2Aa%5C%5C700%3D2030%2Aa%5C%5Ca%20%3D%200.344%5Bm%2Fs%5E%7B2%7D%5D)
Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

where:
m₁ = mass of the car = 2030 [kg]
v₁ = velocity at the initial moment = 0 (the car starts from rest)
Imp₁₋₂ = The impulse or momentum (force by the time)
v₂ = final velocity after the impulse [m/s]
![(2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]](https://tex.z-dn.net/?f=%282030%2A0%29%20%2B%20%28700%2A5%29%3D%282030%2Av_%7B2%7D%29%5C%5C3500%20%3D%202030%2Av_%7B2%7D%5C%5Cv_%7B2%7D%3D1.72%5Bm%2Fs%5D)
Now using the following equation of kinematics, we can determine the distance traveled.

where:
v₂ = final velocity = 1.72 [m/s]
v₁ = initial velocity = 0
a = acceleration = 0.344 [m/s²]
x = distance [m]
![1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]](https://tex.z-dn.net/?f=1.72%5E%7B2%7D%3D0%5E%7B2%7D%20%2B%282%2A0.344%2Ax%29%20%5C%5C2.97%20%3D%200.688%2Ax%5C%5Cx%20%3D%204.32%20%5Bm%5D)
Right answer is option b that is the inner planet may havebeen larger and more gaseous.
Answer:
The ratio of the new force over the original force is 16
Explanation:
Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:

So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:

which is 16 times the original force.
So the ratio of the new force over the original force is 16