Ask question

Ask question

All categories

1 year ago

9

Calculate the potentia energy of a car with a mass of 3800kg that is on a hill 110 meters above sea level? USE 10 instead of 9.8

for the acceleration due to gravity

1 answer:

Arada [10]1 year ago

7 0

Potential energy (PE ) = m g h

Where:

m = mass = 3800 kg

g = acceleration due gravity = 10 m/s^2

h = heigth = 110 meters

Replacing:

PE = 3800 * 10 * 110 = 4,180,000 J

You might be interested in

What is the difference between balanced force and action reaction force

Vilka [71]

Answer:

Balanced forces are equal and opposite forces that act on the same object. ... Action-reaction forces are equal and opposite forces that act on different objects, so they don't cancel out. In fact, they often result in motion.

5 0

3 years ago

Read 2 more answers

What impact can a very large volcanic eruption have on earths climate

Vaselesa [24]

Answer:

It could instantly kill all life on Earth
It could block out the sun and kill off all plants
It could block out the sun and freeze everything
It could throw sulfur millions of miles and kill everything that 'inhales' it

8 0

4 years ago

Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =7 to =1.

Harrizon [31]

1.549×10-19lJ is the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =7 to =1.

The equation E= hcE =hc, where h is Planck's constant and c is the speed of light, describes the inverse relationship between a photon's energy (E) and the wavelength of light ().

The Rydberg formula is used to determine the energy change.

Rydberg's original formula used wavelengths, but we may rewrite it using units of energy instead. The result is the following.

aaΔE=R(1n2f−1n2i) aa

were

2.17810-18lJ is the Rydberg constant.

The initial and ultimate energy levels are ni and nf.

As a change of pace from

n=5 to n=3 gives us

ΔE

=2.178×10-18lJ (132−152)

=2.178×10-18lJ (19−125)

=2.178×10-18lJ×25 - 9/25×9

=2.178×10-18lJ×16/225

=1.549×10-19lJ

Learn more about Rydberg formula here-

brainly.com/question/13185515

#SPJ4

8 0

2 years ago

It is known that heat is added to a gas in sealed container. The container is fitted with a moveable piston.

jasenka [17]

Answer:

d. Not enough information is given to answer this question.

Explanation:

From first law of thermodynamics

Q= W + ΔU

Q=Heat ,W= Work , ΔU=Change in internal energy

If work done by the gas :

It means that W and Q both are positive

Q- W = ΔU

Ii Q > W ,then temperature of the gas will increase.

If Q< W ,Then temperature of the gas will decreases.

If work done on the gas:

Q positive but W will be negative

Q- W = ΔU

Q= W or Q>W or Q< W ,then temperature of the gas will increase.

There are three cases because they did not give any information about the work.That is why option d is correct.

3 0

3 years ago

A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. If your push was directed at an angle

emmasim [6.3K]

<u>Given data:</u>

m= 50 Kg,

W= m×g = 50 × 9.81 = 490.5 N

ramp angle (α) = 30 degrees,

coefficient of friction (μs) = 0.5773,

Push at an angle (Θ) = 40 degrees,

Determine: Push to get box move up (P)=?

From the figure,

Resolving the forces along the plane

W sinα + μs.R = P cos Θ --------------------- (i)

Resolving the forces perpendicular to the inclined plane

W cosα = R+Psin Θ => R= W cosα - Psin Θ -------------- (ii)

Solving (i) and (ii) and keeping <em>μs = tan Φ, Φ = Θ </em>

<em>Pmin = W sin( α +Θ )</em>

<em> = W[ sin α.Cos Θ + cos α.sin Θ]</em>

<em> = 490.5 [ (sin 30.cos40) + (cos30.sin 40)]</em>

<em> = 460.9 N</em>

<em>Minimum push required to move the box up the ramp is 460.9 N</em>

7 0

3 years ago