Answer:
The probability of Dan making less than $255 is 0.5987 or 59.87%
Step-by-step explanation:
Given that:
Mean = μ = $240
SD = σ = $60
We have to find the probability that Dan will make less than $255
First of all, we have to find the z-score of 255
z-score is denoted by z and is given by the formula
Here,
x = 255
Putting the values
Now we have to look at the z-score table to find the probability of 0.25
P(x<255) = 0.5987
Converting into percentage
59.87%
Hence,
The probability of Dan making less than $255 is 0.5987 or 59.87%
I think the answer is D. The U.S. passed laws protecting the beaver.
The formula is V = (4/3) pi * r^3
r = 10 cm^3 = 1000 cm^3 That let's out D
V = (4/3) * 3.14 * 1000
V = (1.3333) * 3.14 * 1000
V = 1333 * 3.14
V = 4185 cm^3
A <<<< ==== answer
The LCD is basically the LCM of the denoenator so
to find LCM of exg 6 and 21, find factors and group
6=2 and 3 (one 2 and one 3)
21=3 and 7 (one 3 and one 7)
lcm=2 and 3 and 7 (include 6 and 21 in the number) (one 2 and one 3 and one 7)
LCM≈LCD
so
17.
denomenators are 2 and x^2
2=2
x^2=x times x
lcm=2 times x times x=2x^2
18.
denomenators are 6 and 9
6=2 and 3
9=3 and 3
LCM=2 times 3 times 3=18
19.
denomenators are z and 7z
z=z
7z=7 and z
lcm=7 times z=7z
20.
denomenators are 5b and 7b^3c
5b=5 and b
7b^3c=7 times b times b times b times c
LCM=7 times 5 times b times b times b times c=7b^3c=7cb^3
21. denomenator=5 and x+2
5=5
x+2=x+2
LCM=5 times (x+2)=5(x+2)=5x+10
22. denomenators are ab and b^2c
ab=a time b
b^2c=b times b times c
LCM=a times b times b times c=ab^2c=acb^2
23. demonenators are m+n and m-n
m+n=m+n
m-n=m-n
LCM=(m+n)(m-n)=m^2-n^2
24.denoenators are k and k^2-2
k=k
k^2-2=k^2-2
LCM=k times (k^2-2)=k^3-2k
For this case, we must indicate which of the given functions is not defined for
By definition, we know that:
has a domain from 0 to infinity.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.
Thus, we observe that:
is not defined, the term inside the root is negative when .
While 
if it is defined for 
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
, your domain is given by all real numbers.
Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.
So, we have:
![y = \sqrt [3] {x-2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx-2%7D)
with x = 0: ![y = \sqrt [3] {- 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B-%202%7D)
is defined.
![y = \sqrt [3] {x + 2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7Bx%20%2B%202%7D)
with x = 0: ![y = \sqrt [3] {2}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%20%5B3%5D%20%7B2%7D)
in the same way is defined.
Answer:
Option b
