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3 years ago

4.5872 _____ √14. A.Greater than, B. Less than, C. equal

Mathematics

2 answers:

Kryger [21]3 years ago

8 0

"A" is the correct answer

oksano4ka [1.4K]3 years ago

7 0

14 squared is 3.7417, so the correct answer is 4.5872 is greater than 14 squared.

Hope I helped! :)

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PLEASE HELP ME ON THIS!!

Ganezh [65]

Answer:

-6

Step-by-step explanation:

This means what value can I plug into -3x-8 so that I get output 10.

g(x)=-3x-8

g(a)=-3a-8

So we are going to solve g(a)=10 for a.

g(a)=10

-3a-8=10

Add 8 on both sides:

-3a =18

Divide both sides by -3:

a =-6

Check it!

g(-6)=-3(-6)-8=18-8=10 and it's good! :)

3 0

3 years ago

The sum of two numbers is 44 . Their difference is 22 .

elena55 [62]

The answer is 11 or 10

5 0

3 years ago

Read 2 more answers

An earthquake measuring 6.4 on the Richter scale struck Japan in July 2007, causing extensive damage. Earlier that year, a minor

a_sh-v [17]

Answer:

Step-by-step explanation

The earthquake measures 6.4 on the Richter scale which struck Japan in Jullu 2007 and caused and extensive damage. Earlier that year, a minor earthquake measuring 3.1 in the Richter scale has stroked in parts of Pennsylvania.

Fomular:

The magnitude of an earthquake is M log(I/S)

where I donates the intensity of the earthquake and S be the intensity of the standard earthquake.

Calculation:

Consider that M1 be the magnitude Japanese earthquake and M2 be the magnitude of the Pennsylvania earthquake and L1 be the intensity of the Japanese earthquake and L2 the intensity of the Pennsylvania earthquake.

Here the magnitude of the Japanese earthquake is M1 = 6.14 and the magnitude of the Pennsylvania is M2 = 3.1

By the use of magnitude of the earthquake fomular M = log I1/S, the intensity of the Japanese earthquake is calculated as follows .

M1 = log I1/S

I1/s = 10

3 0

3 years ago

Find the value of x.

boyakko [2]

Answer:

70.86 degrees

Step-by-step explanation:

cos x = adjacent side / hypotenuse