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dmitriy555 [2]
3 years ago
14

What is the equation 4x-8=7x-35

Mathematics
2 answers:
Drupady [299]3 years ago
6 0
Idk the answer to this equation
zimovet [89]3 years ago
4 0
Move all numbers with variables to one side, and all numbers without to the other

4x (-7x) - 8 (+8) = 7x (-7x) - 35 (+8)

4x - 7x  = -35 + 8

-3x = - 27

Isolate the x, divide - 3 from both sides

-3x/-3 = -27/-3

x = -27/-3

x = 9

hope this helps
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A local water park has two types of season passes. Plan A costs a one-time fee of $125 for admission plus $8 for parking every t
Margarita [4]

Answer:

40+8X=50+23X

8X-23X=50-140

-15X=-90

X=-90/-15

X=7 TRIPS IS THE ANSWER.

PROOF:

140+8*6=50+23*6

140+48=50+138

188=188

4 0
3 years ago
What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?
AlladinOne [14]

Answer:

  -1

Step-by-step explanation:

See the attachment for the polynomial long division. The constant in the quotient is -1.

_____

Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.

That could be a first guess in a "guess and check" solution approach.

<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).

<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2

Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.

6 0
4 years ago
Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1
natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(-5-(-2))^2+(3-1)^2}

r=\sqrt{(-5+2)^2+(2)^2}

r=\sqrt{(-3)^2+(2)^2}

On further simplification, we get

r=\sqrt{9+4}

r=\sqrt{13}

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and r=\sqrt{13}.

(x-(-2))^2+(y-1)^2=(\sqrt{13})^2

(x+2)^2+(y-1)^2=13

Therefore, the equation of the circle is (x+2)^2+(y-1)^2=13.

8 0
3 years ago
Craig’s school has 4 lessons in the morning lessons 1 starts at 8:35 each lesson is 60 minutes long there is a break between les
jasenka [17]

Answer:

12:50 PM.

Step-by-step explanation:

We have been given that Craig’s school has 4 lessons in the morning and lesson 1 starts at 8:35. Each lesson is 60 minutes long. There is a break of 15 minutes between lesson 2 and 3.

We can see that lesson 1 will end at 9:35 AM and second lesson will end at 10:35 AM.

We have been also given that there is a break for 15 minutes between lesson 2 and 3. So third lesson will start at 10:50 AM as lunch break will end at 10:50 AM.

Third lesson will end 60 minutes after 10:50 AM that is 11:50 AM and fourth lesson will end 60 minutes after 11:50 AM that is 12:50 PM.

Therefore, 4th lesson will end at 12:50 PM.    

6 0
3 years ago
The degree of the expression 4x^5y^mz is 10. What is the value of m?
geniusboy [140]
The correct answer is 4 :-)
4 0
3 years ago
Read 2 more answers
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