All categories

3 years ago

What is the value of b^2 0 4ac for the following equation? 2x^2 0 2x 0 1 = 0 04 0 12

Mathematics

1 answer:

tigry1 [53]3 years ago

3 0

<span>2x^2 - 2x - 1 = 0 a = 2, b = -2, c = -1 b^2 - 4ac = (-2)^2 - 4(2)(-1) = 4 + 8 = 12
so the answer is 12
</span>

You might be interested in

Which of the following is not equivalent to 1?

cluponka [151]

Answer:

Step-by-step explanation:

This is because You would still have the Y value as the answer. When you raise a function to the 0 power you will ultimately get on. In this only the coefficient is being raised rather than the whole system.

6 0

3 years ago

ill give brainliest!! Solve these equations for the variable. Check your solutions. please put the answers to this

yawa3891 [41]

Answer:

11. x=5

12. y= -1

13. m= -22

14. m=-4

15.n= 12, -4

16. x=6 ,-5

17. m=4

18. x= 3, -1

Step-by-step explanation:

I hope this help ;-)

8 0

3 years ago

What is 18/32 in simplest form

JulsSmile [24]

Answer:

Step-by-step explanation:

18/32 is the same as 9/16 or 0.5625

7 0

3 years ago

60 POINTS PLEASE HELP FAST!!!! write the equation of a line in standard form that passes through the points (-4,-1) and (1.5,2)

liraira [26]

You find your slope with the equation

(y2-y1)/(x2-x1)

(-1-2)/ -4-1.5)

(-3)/(-5.5)

.54x is your slope

you then plug that into your equation.

y=mx+b

y=.54x+b

you substitute one of our coordinates.

(-4,-1)

-1=.54(-4)+b

-1=-3.45+b

+3.45

2.45=b

your equation is

y=.54x+2.45

standard form

y-.54x=2.45

5 0

3 years ago

What is the reflection image of P(0, 0) after two reflections, first across x = 4 and then across y = -3?

jek_recluse [69]

Answer:

The reflection image of P(0, 0) after two reflections is (8,-6)

Step-by-step explanation:

step 1

Find the coordinates of point P after reflection across x=4

we know that

The distance from point P to the line x=4 is equal to 4 units

(0,0) -----> (4+4,0) ----> (8,0)

The reflection image of P is (8,0)

step 2

Find the coordinates of point (8,0) after reflection across y=-3

The distance from point (8,0) to the line y=-3 is equal to 3 units

(8,0) -----> (8,-3-3) ----> (8,-6)

3 0

3 years ago