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4 years ago

What is the value of b^2 0 4ac for the following equation? 2x^2 0 2x 0 1 = 0 04 0 12

Mathematics

1 answer:

tigry1 [53]4 years ago

3 0

<span>2x^2 - 2x - 1 = 0 a = 2, b = -2, c = -1 b^2 - 4ac = (-2)^2 - 4(2)(-1) = 4 + 8 = 12
so the answer is 12
</span>

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Answer:

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3 years ago

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Answer:

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Step-by-step explanation:

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Please help: linear algebra problem. (Linear combinations)

DochEvi [55]

Answer:

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This tells us that:

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$b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

Ax=b where x is the scalar vector, $\left[\begin{array}{ccc}c\\d\end{array}\right]$ .

So we can write this as:

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3 years ago

Sarah has a collection of nickels, dimes, and quarters worth $28.75. She has 10 more dimes than nickels and twice as many quarte

Ymorist [56]

Answer:

Step-by-step explanation:

Write an equation for each statement:

"Sarah has a collection of nickels, dimes, and quarters worth $15.75."

.05n + .1d + .25q = 15.75

"She has 10 more dimes than nickels"

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"twice as many quarters as dimes."

q = 2d

How many coins of each kind does she have?

Take the 2nd equation and arrange it so n is in terms of d also

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n = (d - 10)

In the 1st equation substitute (d-10) for n and 2d for q:

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.05(d-10) + .1d + .25(2d) = 15.75

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Remember the statement "twice as many quarters as dimes."

q = 2(25)

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n = 25 - 10

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Check our solutions

.05(15) + .1(25) + .25(50) =

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2 years ago