Answer:
the lengths of the sides of the yard.
Step-by-step explanation:
Answer:
f{0) is greater than g(0) and f(2) is greater than g(2).
Step-by-step explanation:
f{0) is greater than g(0) = f(0)=8 and g(0)=2
f(2) is greater than g(2) = f(2)=8 and g(2)= -4
Answer:
A. √3 : 2
D. 3√3 : 6
Step-by-step explanation:
In a triangle described as 30°-60°-90° triangle, the base angles are 90° and 60°
The side with angles 90° and 60° is the shortest leg and can be represented by 1 unit
The hypotenuse side is assigned a value twice the shorter leg value, which is 2 units
From Pythagorean relationship; the square of the hypotenuse side subtract the square of the shorter leg gives the square of the longer side
This is to say if;
The given the shorter leg = 1 unit
The hypotenuse is twice the shorter leg= 2 units
The longer leg is square-root of the difference between the square of the hypotenuse and that of the shorter leg

where the longer leg is represented by side b in the Pythagorean theorem, the hypotenuse by c and the shorter leg by a to make;

<u>Hence the summary is</u>
a=shorter leg= 1 unit
b=longer leg = √3 units
c=hypotenuse=2 units
The ratio of longer leg to its hypotenuse is
=√3:2⇒ answer option A
This is the same as 3√3:6 ⇒answer option D because you can divide both sides of the ratio expression by 3 and get option A

Answers are :option A and D
Answer:
± 
, 
Step-by-step explanation:
See the attached image
This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are:
that correspond to the force of resistance on the mass by the action of the spring and
that is an external force with unknown direction (that does not specify in the enounce).
For determinate
we can use Hooke's Law given by the formula
where
correspond to the elastic constant of the spring and
correspond to the relative displacement of the mass-spring system with respect of his rest state.
We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

Now we apply Newton's 2nd Law and obtaint that...
±
= 




Finally...
± 
We know from the problem that there's not initial displacement and initial velocity, so...
and 
Finally the Initial Value Problem that models the situation describe by the problem is

Answer:
ok lol i guess
Step-by-step explanation: