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Dovator [93]
4 years ago
6

What is 0.0000009/.03 in scientific notation?

Mathematics
1 answer:
meriva4 years ago
7 0
<span>0.0000009 = 9 x 10^-7
</span><span>.03 = 3 x 10^-2

</span>9 x 10^-7/ 3 x 10^-2 = 3 x 10^-5
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Which of the following is an example of a continuous random variable?
matrenka [14]

Answer:

The weight of a bag of potatoes.

Step-by-step explanation:

Continuous variable are those which can take infinite number of value between any two values.

For example: amount of sand : it can take any value  let say between 100 and 101 kg. Such 100.1 kg,  100.888 kg and so on.

Discreet variable are those which takes values which can take on natural number values such 1,2 , and so on.

Example : no of students of class:  no. of students can only be natural numbers  like 45, 35 and so on

_________________________________________________

lets evaluate options now

a. The number of cars in a parking lot.--> it is Discreet variable as no. of cars can be in terms of natural numbers

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The weight of a bag of potatoes. it is continuous variable as weight can take infinite set of values like 200 kg, 200.11 kg, 200. 111119 kg and etc.

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The number of repairs at a computer shop over the course of the week.

--> it is Discreet variable as number of repairs will also vary in natural number form like 10 repairs, 20 repairs etc. there cannot be 10. repairs.

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d. The total runs scored in a cricket game

---> It is Discreet variable as number of runs scored is also natural number like 251 runs, 301 runs. Runs cannot be 300.2 runs.

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Hence, correct answers is  

The weight of a bag of potatoes.

7 0
3 years ago
Compute the value of the following improper integral if it converges. If it diverges, enter INF if it diverges to infinity, MINF
Phoenix [80]

Answer:

INF for first while D for second

Step-by-step explanation:

Ok I think I read that integral with lower limit 1 and upper limit infinity

where the integrand is ln(x)*x^2

integrate(ln(x)*x^2)

=x^3/3 *ln(x)- integrate(x^3/3 *1/x)

Let's simplify

=x^3/3 *ln(x)-integrate(x^2/3)

=x^3/3*ln(x)-1/3*x^3/3

=x^3/3* ln(x)-x^3/9+C

Now apply the limits of integration where z goes to infinity

[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]

[z^3/3*ln(z)-z^3/9]- (1/9)

focuse on the part involving z... for now

z^3/9[ 3ln(z)-1]

Both parts are getting positive large for positive large values of z

So the integral diverges to infinity (INF)

By the integral test... the sum also diverges (D)

3 0
3 years ago
Find three positive consecutive integers such that the product of the smallest and the largest is 17 more than three times the m
trapecia [35]
There are two answers to this question
the first possible answer is 5, 6, and 7 and the second possible answer is -4, -3, and -2


Step-by-step explanation:

let the three numbers be (x-1), x, and (x+1)
the product of the smallest and largest number is 17 more than 3 times the middle number, or
(x-1)(x+1) = 3x+17, or
x^2-1 = 3+17, or
x^2-3x-18 = 0
(x-6)(x+3) = 0
So x = 6 or -3
Then just subtract one and add one to get the other integers. the three numbers are 5, 6, and 7 or -4, -3, and -2
3 0
3 years ago
Solve the proportion P/6 = 24/36
olya-2409 [2.1K]
P is 4 as 6 divide 36 is 6 so 6 divide 24 is 4 so


P=4
6 0
3 years ago
Read 2 more answers
Which of the following have the correct solution? Check all
Neko [114]

Step-by-step explanation:

To do this, we will substitute the x values to their corresponding equations,

1)

2x + 5 \\  = 2(7) + 5 \\  = 14 + 5 \\  = 19

Given 2x + 15 = 19

Calculated 2x + 15 = 19

Given = Calculated, this solution is correct.

2)

3 + x + 2 -x \\  = 3 + 3 + 2 - 3 \\  = 8 - 3 \\  = 5

Given 3 + x + 2 - x = 16

Calculated 3 + x + 2 - x = 5

Given not equal to calculated, this solution is incorrect.

3)

\frac{x + 2}{5}  \\  =  \frac{8 + 2}{5}  \\  =  \frac{10}{5}  \\  = 2

Given (x+2)/5 = 2

Calculated (x+2)/5 = 2

Given = Calculated, this solution is correct.

4)

6 = 2x - 8 \\ 2x - 8 = 6

2x - 8  \\  = 2(7) - 8 \\  = 14 - 8 \\  = 6

Given 2x - 8 = 6

Calculated 2x - 8 = 6

Given = Calculated, this solution is correct.

5)

14 =  \frac{1}{3} x + 5 \\  \frac{1}{3} x + 5 = 14

\frac{1}{3} x + 5 \\  =  \frac{1}{3}(18) + 5 \\  =  \frac{18}{3}   + 5 \\  = 6 + 5 \\  = 11

Given 1/3x + 5 = 14

Calculated 1/3x + 5 = 11

Given not equal to Calculated, this solution is not correct.

Therefore the Correct solutions are 1,3 and 4.

8 0
3 years ago
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