Answer:
Step-by-step explanation:
C) x1/4y1/2
34 base five to 34 base ten is 19.
<u>Step-by-step explanation:</u>
Basically , In order to convert 34 from base 5 to base 10 , We skip consecutive 5 numbers after counting 5 numbers as shown below in table in base-5 table and , just increment 1 in base-10 table
<u>Base- 5 </u> <u>Base-10</u>
1 1
2 2
3 3
4 4
10 5
12 6
13 7
14 8
20 9
....... ....
34 19
34 base five to 34 base ten is 19.
Write the multiples of 5 (1,5,25,125,....) based on the no.of digits given. Then multiply and add to convert it into base 10
5 1
------------
3 4
------------
5 (3)+ 1(4) = 15+4 = 19
Answer:
-8
Step-by-step explanation:
x^(m/n)=![\sqrt[n]{x}^m](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%5Em)
(-32)^(3/5)
=![\sqrt[5]{(-32)} ^3](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%28-32%29%7D%20%5E3)
=(-2)^3
=-8
Answer:
31/40
Step-by-step explanation:
The question is incomplete. Here is the complete question with appropriate diagram.
The circle below has an area of 314 square centimeters, and the square inside the circle has a side length of 2 centimeters.
What is the probability that a point chosen at random is in the blue region?
Given the area of the circle to be 314cm², we need to get the diameter of the circle first since the diameter of the circle is equivalent to length of the side of the square inscribed in it.
Using the formula Area of a circle = πr²
314 = 3.14r²
r² = 314/3.14
r² = 100
r = 10 cm
Diameter of the circle = 2*10 = 20 cm
Area of a square = Length * length
Area of the outer square = 20*20 = 400cm²
Area of the inner square with side length 2cm = 2*2 =4cm²
Area of the shaded region = Area of the square - Area of the inner square
= 314-4 = 310cm²
The probability that a point chosen at random is in the blue region = Area of the shaded region/total area of the outer square
= 310/400
= 31/40
This equation would not be correct.
In the left expression, cscAsecA contains the variable 'e' which is not present in the second expression.