Question

How many real number solutions does the equation have 0=5x^2+2x-12

Answer 1

 Rearrange the equation to standard form of a quadratic equation (ax^2+bx+c=0) by switching sides: 5x^2+2x-12=0. Now, use the quadratic equation formula to solve. You should come out with x_1=sqrt61-1/5 and x_2=-1+sqrt61/5. Thus, your answer is B, or two solutions.

Answer 2

Answer:

A.  two solutions

Step-by-step explanation:

To find the number of real solutions the equation is having, we need to solve first;

0=5x²+2x-12

This equation can be re-written as;

5x²+2x-12 = 0

We will use the formula method to solve

Using formula method;

x = -b ±√b² -  4ac  / 2a

From the equation given,

a = 5   b =  2   and c=-12

x = -2 ± √2² - 4(5)(-12)  /  2(5)

x = -2 ± √4 + 240  /  10

x = -2/10   ± √244 /10

x = $\frac{-1}{5}$ ±  1.56

x = - 0.2  ±  1.56

Either    x = -0.2 + 1.56     or     x = -0.2 - 1.56

Either     x  = 1.36                or     x = -1.76

Therfore, this equation have two real number solutions