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aivan3 [116]
3 years ago
8

a company uses two vans to transport workers from a free parking lot to the workplace between 7:00 and 9:00 am . one van has 6 m

ore seats than the other. the smaller van makes two trips every morning while the larger one makes only one trip. the two vans can transport 57 people , maximum. let X be the seats in the small van and y the seats in the large van . how many seats does the larger van have?
Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
X is the seats in the small van.

y is the seats in the large van = (x + 6). Since the large has 6 more seats.

Since the 2 vans can transport 57 people.

Small van makes 2 trips = 2x.

Large van makes one trip = (x + 6).

2x + (x +6) = 57

2x + x + 6 = 57

3x + 6 = 57

3x = 57 -6

3x = 51

x = 51/3

x = 17.

The larger van has (x + 6) = (17 + 6) = 23.

The larger van has 23 seats. 
olganol [36]3 years ago
4 0
Y - x = 6
y + 2x = 57 

2y - 2x =12
y + 2x = 57 

∴3y = 69
   y = 23
 

23 - x = 6 
-x = -17 
x =17

large van = 23
small van = 17
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Step-by-step explanation:

Remark

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Formula

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Find the cardinal number of the set<br> C = {x|x € N, 30 &lt; x &lt; 56 and x is divisible by 6},
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<h3>Answer: 4</h3>

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Explanation:

We're given the following

C = \{ x | x \in \mathbb{N}, \ 30 < x < 56, \ \text{ x is divisible by 6}\}

which means that we have a set of natural numbers between 30 and 56, excluding both endpoints, and the set of numbers are also multiples of 6.

So looking at the multiples of 6 that are between 30 and 56 leads us to

{30, 36, 42, 48, 54}

but we cross off 30 as we want x to be larger than that, so we get this updated final list

{36, 42, 48, 54}

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Step-by-step explanation:

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So, 4 men and 6 boy's 1 day work is \frac{4}{x} and \frac{6}{y}

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Since, 4 men and 6 boys complete the work in 5 days and 3 men and 4 boys complete the work in 7 days.

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So, the number of days taken by 1 men alone and 1 boy alone are 35 days and 70 days respectively.

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4 years ago
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