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aivan3 [116]
3 years ago
8

a company uses two vans to transport workers from a free parking lot to the workplace between 7:00 and 9:00 am . one van has 6 m

ore seats than the other. the smaller van makes two trips every morning while the larger one makes only one trip. the two vans can transport 57 people , maximum. let X be the seats in the small van and y the seats in the large van . how many seats does the larger van have?
Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
X is the seats in the small van.

y is the seats in the large van = (x + 6). Since the large has 6 more seats.

Since the 2 vans can transport 57 people.

Small van makes 2 trips = 2x.

Large van makes one trip = (x + 6).

2x + (x +6) = 57

2x + x + 6 = 57

3x + 6 = 57

3x = 57 -6

3x = 51

x = 51/3

x = 17.

The larger van has (x + 6) = (17 + 6) = 23.

The larger van has 23 seats. 
olganol [36]3 years ago
4 0
Y - x = 6
y + 2x = 57 

2y - 2x =12
y + 2x = 57 

∴3y = 69
   y = 23
 

23 - x = 6 
-x = -17 
x =17

large van = 23
small van = 17
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Step-by-step explanation:

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Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

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                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

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Amiraneli [1.4K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Step Two
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Step Three
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