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IrinaVladis [17]
4 years ago
6

What is 4,264 rounded to the nearest hundred?

Mathematics
2 answers:
Alinara [238K]4 years ago
4 0

Answer:

Round 4264 to the nearest hundred so the answer is 4300.

earnstyle [38]4 years ago
4 0

Answer:

4300

Step-by-step explanation:

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How many fluid ounces are there in 3 pints and 4 fluid ounces?
hram777 [196]

Answer:

52 US fluid ounces

Step-by-step explanation:

6 fluid ounces

How many fluid ounces in a pint? There are 16 fluid ounces in a pint.

5 0
3 years ago
Read 2 more answers
Find the scale factor and ratio of perimeters for a pair of similar octagons with areas 9 ft^2 and 16 ft ^2 .
tangare [24]

Answer:

3/4 ratio

Step-by-step explanation:

This is the answer

5 0
2 years ago
Brianna is twice as old as James . David is four times as old as James. Brianna is 20 years younger than David. How old is David
IrinaK [193]

Answer:

David might be 40

Step-by-step explanation:

Brianna = 20 + 20 = 40 = David

James = 10 x 2 = Brianna

David = 40 - 20 = Brianna

8 0
4 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0

Solve this equation we get

p(t)=p_0e^{kt}---(1)

where p is the present population

p₀ is the initial population

If the  initial population as doubled in 5 years

that is time t = 5 years

We get

2p_o=p_oe^{5k}\\\\e^{5k}=2

Apply In on both side to get

Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}

Substitute k=\frac{In2}{5}  in p(t)=p_oe^{kt} to get

\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}

Given that population of a community is 9000 at 3 years

substitute t = 3 in {p(t)=p_oe^{\frac{In2}{5}t }}

p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8

<h3>Therefore, the initial population is 5937.8</h3>
7 0
3 years ago
Name the property illustrated by the equation.<br> -6xy + 0 = -6xy
Rina8888 [55]

Answer:

identity    

Step-by-step explanation:

7 0
4 years ago
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