Answer:
Total area = 31.5 unit²
Step-by-step explanation:
Assume 1 block = 1 unit²
Divide diagram into 3 part
1. 5 by 5 block square
2. 2 by 2 block triangle(1)
2. 3 by 3 block triangle(2)
Area of square = side × side
Area of square = 5 × 5
Area of square = 25 unit²
Area of triangle(1) = [1/2][base][height]
Area of triangle(1) = [1/2][2][2]
Area of triangle(1) = 2 unit²
Area of triangle(2) = [1/2][base][height]
Area of triangle(2) = [1/2][3][3]
Area of triangle(2) = 4.5 unit²
Total area = Area of square + Area of triangle(1) +Area of triangle(2)
Total area = 25 unit² + 2 unit² + 4.5 unit²
Total area = 31.5 unit²
Answer:
b and c
Step-by-step explanation:
Answer:
they are both 0 since they would not appear on a graph
Step-by-step explanation:
V=x³-7x+6, V=(x-2)(x+3)*h
(x-2)(x+3)*h=x³-7x+6
h{x²+x-6}=x³-7x+6
h=(x³-7x+6)/(x²+x-6)
Therefore h=x-1
-----------------------------
Check answer:
V=(x-2)(x+3)(x-1)
=(x-1)(x²+x-6)
=x(x²+x-6)-1(x²+x-6)
=x³+x²-6x-x²-x+6
=x³-6x-x+6
=x³-7x+6
Answer:
Your teacher is right, there is not enough info
Step-by-step explanation:
<h3>Question 1</h3>
We can see that RS is divided by half
The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS
So P is not on the perpendicular bisector of RS
<h3>Question 2</h3>
We can see that PD⊥DE and PF⊥FE
There is no indication that PD = PF or ∠DEP ≅ FEP
So PE is not the angle bisector of ∠DEF
