Question

How many solutions does the system have? x = -4y + 4 2x + 8y = 8

Answer 1

Solutions 

To solve the system lets use substitution 

$2x+8y=8$ 

$2(-4y+4)+8y=8$ 

$8=8$ 

This is a dependent system. 

------------ Now lets solve the same system using Elimination  

Our first step will be to multiply the given system by 2

$2x+8y=8 2x+8y=8$

$0=0$ 

There are Infinitely Many Solutions