To make a positive profit p(x)>0 we need to make:

Now we solve this for x:

We have:
a = -2
b = 7
c = -3
We will use formula for quadratic equation:

We got two solutions. One is fraction other is whole number. We will not consider fraction because the amount of muffins sold must be whole number. So our solution is:
x>3
Answer:
Yes
Step-by-step explanation:
Assuming that the question is asking for -1 to be plugged in as x
4(-1)-3≤5
-4-3≤5
-7≤5
Answer:
All of them
Step-by-step explanation: