Draw the electric field lines between a proton and an electron. According to Coulomb's law, how would the electrical force betwe
en these particles change if the product of their electrical charge increased?
1 answer:
Explanation:
An electron has a negative charge and a proton is a positively charged particle. Electric field lines are used to express the direction of the electric field. For a positive charge, it is outwards while for a negative charge it is inwards. The attached figure shows the electric field lines between a proton and an electron. The field lines emerge from proton and terminate at electron.
The electrical force between charges is given by :
r is the distance between charges
The force is directly proportional to the product of charges. It means that if the product of electrical charge increased, it means that the electrical force will increase proportionally.
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Answer:
Final temperature is 302 K
Explanation:
You can now initial volume with ideal gas law, thus:
V =
Where:
n are moles: 2 moles
R is gas constant: 0,082
T is temperature: 300 K
P is pressure: 1 atm
V is volume, with these values: <em>49,2 L</em>
The work in the expansion of the gas, W, is: 1216 J - 34166 J = <em>-32950 J</em>
This work is:
W = P (Vf- Vi)
Where P is constant pressure, 1 atm
And Vf and Vi are final and initial volume in the expansion
-32950 J = -1 atm (Vf-49,2L) ×
Solving: <em>Vf = 49,52 L</em>
Thus, final temperature could be obtained from ideal gas law, again:
T =
Where:
n are moles: 2 moles
R is gas constant: 0,082
P is pressure: 1 atm
V is volume: 49,52 L
T is final temperature: <em>302 K</em>
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I hope it helps!