The empirical formula of this compound is
<u>Given the following data:</u>
<u>Scientific data:</u>
- Molar mass of hydrogen (H) = 1.0 g/mol.
- Molar mass of sulfur (S) = 32 g/mol.
- Molar mass of oxygen (O) = 16 g/mol.
To determine the empirical formula of this compound:
Note: We would assume that the mass of the compound is 100 grams.
Hence, the mass of its constituent elements are:
- Mass of hydrogen (H) = 2.00 grams
- Mass of sulfur (S) = 32.7 grams
- Mass of oxygen (O) = 65.3 grams
Next, we would determine the number of moles of each element by using this formula:
<u>For </u><u>hydrogen</u><u> (</u><u>H</u><u>):</u>
Number of moles = 2.0 moles
<u>For </u><u>sulfur</u><u> (</u><u>S</u><u>):</u>
Number of moles = 1.0 moles
<u>For </u><u>oxygen</u><u> (</u><u>O</u><u>):</u>
Number of moles = 4.0 moles
Empirical formula =
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Answer:
Does a reaction occur when aqueous solutions of copper(II) nitrate and calcium chloride are combined?
Explanation:
The given reaction is an example of a chemical double displacement reaction.
The mutual interchange of the ions takes place.
The balanced chemical equation of the reaction is:
All the products formed are also highly soluble.
So, all the ions are spectator ions.
Hence, all will cancel with each other and ions remain in the net ionic equation and hence, the reaction does not take place.
From the combustion of octane, the formaldehyde will be formed as this equation:
C8H18 + O2 → CH2O + H2O this is the original equation but it is not a balanced equation, so let's start to balance it:
the equation to be balanced so the number of atoms on the right side of the equation sholud be equal with the number of atoms on the lef side.
-we have 8 C atoms on left side and 1 atom on the right side so we will try putting 8 CH2O on the right side instead of CH2O
C8H18 + O2 → 8 CH2O + H2O
we have 2 O atoms on the left side and 9 atoms on the right side so we will try first to put 9 O2 instead of O2 on the left side and put 2H2O on the right side and put 16 CH2O instead of 8 CH2O to make the atoms of O are equal on both sides = 18 atoms
C8H18 + 9 O2 → 16 CH2O + 2H2O
put now we have 8 atom C on the left side and 16 atom on the right side so, we will put 2 C8H18 instead of C8H18 now we get this equation:
2C8H18 + 9O2 →16 CH2O + 2H2O
-now we have 36 of H atoms on both sides.
- and 16 of C atoms on both sides.
- and 18 of O atoms on both sides.
now all the number of atoms of O & C & H are equal on both sides
∴ 2C8H18 + 9O2 → 16 CH2O + 2 H2O
is the final balanced equation for the formation of formaldehayde
Answer:
=342g
Explanation:
atomic mass of C = 12g
atomic mass of H = 1g
atomic mass of O = 16g
Solution;
C12 H22 O11
= 12 (12) + 22 (1) + 11(16)
= 144+ 22 + 176
= 342g
Answer:
See explanation.
Explanation:
Hello there!
In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:
Thus, we proceed as follows:
Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:
Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:
Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:
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