Find the altitude of an isosceles triangle with a vertex angle of 70° and a base of 246

1 answer:

7 0

The base angles are both equal to (180-70) / 2 = 55 degrees

and 1/2 base = 123

so we have tan 55 = a / 123 where a = altitude
a = 123 * tan55 = 175.66

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