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3 years ago

Find the altitude of an isosceles triangle with a vertex angle of 70° and a base of 246

1 answer:

7 0

The base angles are both equal to (180-70) / 2 = 55 degrees

and 1/2 base = 123

so we have tan 55 = a / 123 where a = altitude
a = 123 * tan55 = 175.66

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Ans this pls i wil amrk as brainlist

Law Incorporation [45]

Answer:

9:01

2:36

3:40

Step-by-step explanation:

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3 years ago

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$

$\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}$

8 0

2 years ago

PLSSSSSSS HELPPPPPPPPPP MEEEEEEEEEEEEEE

lozanna [386]

Answer:

x= 16

Step-by-step explanation:

8x + 50 = 178

8x = 178- 50

8x = 128

x = 128/8

x = 16

8 0

2 years ago

Read 2 more answers

The measure of one a cite angle of a right triangle is 6 less than twice the measure of the other acute angle find the measure o

jeka57 [31]

Answer:

32°, 58°

Step-by-step explanation:

Let one acute angle measure x.

The other acute angle measures 2x - 6.

The sum of the measures of the acute angles of a right triangle is 90.

x + 2x - 6 = 90

3x - 6 = 90

3x = 96

x = 32

2x - 6 = 2(32) - 6 = 58

Answer: 32°, 58°

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2 years ago

If 72 males and 108 females responded to your fashion survey, what percentage were females?

Sergio039 [100]

60% is the percentage of the females who responded to the survey.

7 0

3 years ago