130 degrees.
ADB = 90 degrees
BDT=40 Degrees
Therefore, TDS = ADB(90)+BDT(40)=130 degrees
3x + 2y = -26
4x - 5y = -4
To eliminate, we are going to cancel out the y
So multiply the first equation by 2.5, and you'll get
7.5x + 5y = -65
Add this equation to the second, and you'll get
11.5x = -69
Divide by 11.5 on both sides, and you get
x = -6
Now plug the -6 into the first equation, and you get
3(-6) + 2y = -26
Solve
-18 + 2y = -26
2y = -8
y = -4
Answer:
They are perpendicular.
Step-by-step explanation:
When we convert the equation 6x-2y=-5 into y=mx+b form, it changes into y=3x-5/2. Since we know that perpendicular slopes are opposite reciprocal, the opposite reciprocal of -x/3 is 3. So, we know that these 2 slopes are perpendicular.
Answer:
Option C
Step-by-step explanation:
same logic as in 2D problems. if C wasn't true, then the two planes couldn't be parallel
