Answer:
40951
Step-by-step explanation:
Using the principles of inclusion - Exclusion
Where C(n,r)=n!/(n-r)!r!
Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000
Total Number of elements in each pair including number repetition of sets is given as
=(1000) × C(5, 2) =10000
Number of elements in each triple of sets is given as
=(100) × C(5, 3) =1000
Number of elements in every four sets
=(10) × C(5, 4)=50
Number of elements in every one set
(1) × C(5, 5)=1
Therefore total number of unique elements=50000-10000+1000-50+1
=40951
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<h2><em>All of it. Be kind to your mother.</em></h2><h2><em></em></h2><h2><em></em></h2><h2><em></em></h2><h2><em>In all seriousness, 15% of 100 is itself. 15. If it was 27%, it'd be 27. So on and so forth.</em></h2>
