The quilt is 2.44 m long and 1.83 m wide what is the area of the quilt in square feet

Tamara makes 12 identical flower arrangements, each with 3 roses and some carnations. She uses a total of 96 flowers.

storchak [24]

Answer:

5 carnations in each arrangement

Total of 60 carnations used

Step-by-step explanation:

First calculate how many flowers are in each arrangement by dividing the total number of flowers by the number of arrangements:

96 ÷ 12 = 8

Given each arrangement has 3 roses, subtract 3 from 8 to find the number of carnations in each arrangement:

8 - 3 = 5

Therefore, there are 5 carnations in each arrangement

Total number of carnations used = 5 x 12 = 60

5 0

2 years ago

Eastridge High School’s Student Government Association is holding a raffle to raise money for a local food pantry. They have spe

Blababa [14]

"Interpret the rate of change and the y-intercept.

"

Rate of change is 5. Each ticket costs 5$.

Y-intercept is (0,-17). They spent $17 on supplies before they sold tickets.

(Sorry, you probably already know the answer)

5 0

3 years ago

The volume of a packing box is 5 – x cubic feet. The width of the box is x feet and the length is x – 2 feet. The height is give

photoshop1234 [79]

By definition we have that the volume is given by
V = h * w * l
where
V: Volume
h: height
w: width
l: length
Clearing the height we have:
h = V / (w * l)
h = (5 - x) / ((x) * (x - 2))
The expression is not defined for the values of x that make the denominator zero:
((x) * (x - 2)) = 0
x = 0
x = 2
Answer
h = (5 - x) / ((x) * (x - 2))
x = 0
x = 2

4 0

3 years ago

Directions: Select all the correct answers.

Kay [80]

The correct answer is C and D .

4 0

3 years ago

Some research suggests that police officers are more likely to make an arrest in the presence of bystanders. If mentally disorde

zmey [24]

Answer:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

$p_v =P(t_{(19)}>1.638)=0.0589$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=7.03$ represent the sample mean

$s=9.42$ represent the sample standard deviation

$n=20$ sample size

$\mu_o =3.58$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 3.58 :

Null hypothesis: $\mu \leq 3.58$

Alternative hypothesis: $\mu > 3.58$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{7.03-3.58}{\frac{9.42}{\sqrt{20}}}=1.638$

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since is a right tailed test the p value would be:

$p_v =P(t_{(19)}>1.638)=0.0589$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the true mean is not significantly higher than 3.58 at 5% of signficance.

7 0

3 years ago