Why not draw the graph of y=|x|? It has a v-shape, and the vertex is at (0,0).
The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward. The smallest value that y can have is therefore -3.
Can you now figure out the range of f(x)?
One of the very nice features of the metric system of measurements is that there is a set of standardized prefixes that can be applied to any of the units. Some of the more common ones are
.. micro- . . . one millionth
.. milli- . . . . one thousandth
.. centi- . . . .one hundredth
.. kilo- . . . . .one thousand
Thus, one millimeter is 1/1000 = 0.001 meter. There are 1000 of them in 1 meter, so
.. 16 m = 16000 mm
Answer: Y=(
) x-7
Step-by-step explanation:
Normally You would need to simplify all of them, to see what their values are like.
Already from the start, however, we can see that 9n + 3 + 2 and 9n + 11 isnt the same value. Based on this, we should only need to simplify one of the other, to get either 9n + 5 or 9n + 11.
Lets pick the upper one.
(4n + 3) + 5n + 8 - 6
4n + 3 +5n + 2
9n + 5.
This indicated that 9n+11 is the odd one.
To make sure, we can solve the next one:
(4n + 5n) + (3 + 8 - 6)
9n + 5
Which indicated the same thing.
9n+11 is the "outsider", which means:
9n + 11 is the correct answer for this task.