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kirza4 [7]
3 years ago
5

If the 16 boys in the classroom are 40% of the class how many students are there in the class

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0

Answer:

56

Step-by-step explanation:

40+16=56

AlladinOne [14]3 years ago
5 0

Answer:

40

Step-by-step explanation:

Set up the equation.

Let the full number of people in the classroom = x

(40%) x = 16                Change 40% to a fraction

(40/100) x = 16            Reduce 40/100 to a decimal

0.4 x = 16                     Divide by 0.4

0.4/0.4 x = 16/0.4

x = 40

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- 24 - 16x(  - 1) \\ 6 { }^{2}  \div 9

negative 24 minus 16x (-1) divided by 6^2 divided by 9

ANSWER

four divided by 81 and than X minus 24

4 \div 81x - 24
5 0
3 years ago
In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

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Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
Use the Pythagorean theorem and the following diagram to help you find the area and perimeter of the following triangle. Please
Mekhanik [1.2K]

Answer:

Perimeter = 30

Area = 30

Step-by-step explanation:

(x+8)^2 -x^2 = 12^2

x^2 +16x +64 - x^2 = 144

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16x = 80

x = 5

Double check:

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Perimeter:

12+5+13=30

Area(\frac{1}{2}bh):

\frac{1}{2} × 12 × 5 = 30

5 0
3 years ago
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expeople1 [14]
Y – y1 = m(x – x1)

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Y+1=-5(x-2)
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3 years ago
Which of the following is equal to [(x^2y^3)^-2/(x^6y^3z)^2]^-3
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Answer:

A,B,D

Step-by-step explanation:

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4 0
3 years ago
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