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3 years ago

I need help with 3/9-1/10 in fractions

Mathematics

1 answer:

mars1129 [50]3 years ago

4 0

7/30

Step-by-step explanation:

convert them to a common denominator by multiplying top and bottom to have a common denominator of 90. It becomes 30/90-9/90. Then you get 21/90 which reduces to 7/30.

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Determine the length of the line segment shown. line segment from negative 10 comma 9 to 5 comma negative 1 4 units 18 units 19

user100 [1]

The length of the line segment is (b) 18 units

<h3>How to determine the length of the line segment?</h3>

The line segment is given as

ine segment from negative 10 comma 9 to 5 comma negative 1

This can be rewritten as

line segment from (-10, 9) to (5, -1)

The length of the line segment is then calculated using the following distance formula

distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Where

(x, y) = (-10, 9) to (5, -1)

Substitute the known values in the above equation, so, we have the following representation

Length = √[(-10 - 5)² + (9 + 1)²]

Evaluate

Length = 18

Hence, the length is 18 units

Read more about distance at

brainly.com/question/7243416

#SPJ1

4 0

1 year ago

Read 2 more answers

Which quadratic equation has roots - 2 and 1/5 :

Sladkaya [172]

Answer:

$5 {x}^{2} \: + \: 8x \: - 2 \: = \: 0$

Step-by-step explanation:

$sum \: of roots = - 2 + \frac{1}{5} = - \frac{8}{5} \\ product \: of \: roots = - 2 \times \frac{1}{5} = - \frac{2}{5} \\ from \: general \: equation \\ a {x}^{2} + bx + c = 0 \\ {x}^{2} + \frac{8}{5} x \: - \frac{2}{5} = 0 \\ 5 {x}^{2} \: + \: 8x \: - 2 \: = \: 0$

7 0

3 years ago

Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates: