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garri49 [273]
4 years ago
7

Find the explicit formula for -3,-33,-63,-93

Mathematics
1 answer:
bagirrra123 [75]4 years ago
5 0

Answer:

a n = -3+(n-1)-30

Step-by-step explanation:

-3 - 30 = -33

-33 - 30 = -63

-63 - 30 = -93

The common difference here is -30. d = -30

The explicit formula is a n = a1 + (n-1)d

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What is the answer for this 8k−5(−5k+3)
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If sin theta equals 12 divided by 13 and theta is in quadrant 2 cos20 equals? and cos theta equals?
Anni [7]

Answers:

  • cos(2theta) = -119/169
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=====================================================

The given info is:

  • sin(theta) = 12/13
  • theta is in quadrant II

From that, we can use the pythagorean trig identity to find that cos(theta) = -5/13. Keep in mind that cosine is negative in quadrant II.

Now use the trig identity below to compute cos(2theta)

\cos(2\theta) = \cos^2(\theta)-\sin^2(\theta)\\\\\cos(2\theta) = \left(\frac{-5}{13}\right)^2-\left(\frac{12}{13}\right)^2\\\\\cos(2\theta) = \frac{25}{169}-\frac{144}{169}\\\\\cos(2\theta) = \frac{25-144}{169}\\\\\cos(2\theta) = -\frac{119}{169}\\\\

Other options you could use are these identities

\cos(2\theta) = 2\cos^2(\theta)-1\\\\

or

\cos(2\theta) = 1-2\sin^2(\theta)\\\\

3 0
3 years ago
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