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bonufazy [111]
3 years ago
5

Solve the equation x/9 = 6

Mathematics
2 answers:
bija089 [108]3 years ago
5 0

Answer:

Step-by-step explanation:

Molodets [167]3 years ago
3 0

Answer: x=54

Step-by-step explanation:

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3x + 1 = -2 (solve for x)
professor190 [17]

Answer:

x = -1

Step-by-step explanation:

3x + 1 = -2

Subtract 1 from both sides.

3x = -2 - 1

Simplify -2 - 1 to 3.

3x = -3

Divide both sides by 3.

x = -1

8 0
3 years ago
The legth of a rectangle is 15 inches less then twice its width, w. If the perimeter of the rectangle is 96 inches what is the l
KATRIN_1 [288]

Answer:

length of the rectangle=27"

Step-by-step explanation:

length be = l; width be = b

2b-15= l

perimeter= 2(l+b)

=2(2b-15+b)=96

=2(3b-15)  =96

3b-15 .=48

3b=48+15=63

b=21. Therefore l = (2 x 21)  - 15=42-15  =27"

8 0
3 years ago
How do i solve step by step s+2 1/2s+20=48 ?
sammy [17]
S+(2+1/2)s+20=48

2/2s+5/2s=48-20

7/2s=28

7s=28*2=2(20+8)=40+16

7s=56

s=56/7

s=8
8 0
3 years ago
Read 2 more answers
)Two similar triangles are shown on the following coordinate grid:
muminat

Answer:

Reflection across the y-axis and a dilation by a factor of 2.

Step-by-step explanation:

Comparing the points from the pre-image, ABC, to the image, A'B'C', we see that both x- and y-coordinates seem to be doubled from the pre-image to the image. However, the sign of the x-coordinates in the image is different; this means that the x-coordinates are negated.  A reflection across the y-axis will negate the x-coordinates.

To double both the x- and y-coordinates, we would then apply a dilation by a factor of 2, as the scale factor gets multiplied by every coordinate.

4 0
3 years ago
Read 2 more answers
Write the word or phrase that best completes each statement or answers the question. Solve the problem.
pogonyaev

Answer:

z(max)  = 2350

x₁  =  18          x₂  =  10

Step-by-step explanation:

                             Vol (ft³)         W (p)    Income ($)

Cargo A  (x₁)             50              200          75

Cargo B  (x₂)            10               360          100

Max load limit       1000            7200

Objective Function

z  =  75*x₁   +  100*x₂

Constraints:

Volume constraint:

50*x₁  +  10*x₂  ≤ 1000

Weight constraint:

200*x₁  +  360*x₂  ≤ 7200

Model:

z  =   75*x₁   +  100*x₂       to maximize

Subject to:

50*x₁  +  10*x₂  ≤ 1000

200*x₁  +  360*x₂  ≤ 7200

x₁  ≥  0        x₂  ≥ 0    x₁  and x₂  integers

After 6 iterations with an on-line solver optimal solution is:

z(max)  = 2350

x₁  =  18          x₂  =  10

6 0
3 years ago
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